【发布时间】:2016-10-27 14:07:31
【问题描述】:
快速提问,我在创建自己的 TreeSet 矩形比较器时遇到了很多麻烦。这是我拥有的代码,但我非常迷茫。我想比较矩形的面积并按升序对它们进行排序。
import java.util.TreeSet;
import java.awt.Rectangle;
import java.util.Comparator;
public class RectComp implements Comparator<Rectangle>
{
private double width;
private double height;
public RectComp(Comparator comp)
{
this.width = width;
this.height = height;
}
public double getArea()
{
return width * height;
}
public int compare(Rectangle r1, Rectangle r2)
{
double diff = r1.getArea() - r2.getArea();
if (diff < 0)
return -1;
else if (diff == 0)
return 0;
else
return 1;
}
public static void main(String[] args)
{
TreeSet<Rectangle> set = new TreeSet<>(new RectComp());
set.add(new Rectangle(1, 10));
set.add(new Rectangle(10, 1));
set.add(new Rectangle(5, 3));
set.add(new Rectangle(5, 2));
set.add(new Rectangle(5, 1));
for (Rectangle r : set) {
System.out.println(r);
}
}
}
【问题讨论】:
标签: java comparator treeset