如何计算两个选定日历日期之间的总天数答案

【问题标题】：How to calculate the total days between two selected calendar dates如何计算两个选定日历日期之间的总天数
【发布时间】：2015-07-08 03:23:29
【问题描述】：

假设我的 startDate = 7/16/2015 和 endDate = 7/20/2015。这 2 个日期存储在 SharePoint 列表中。

如果用户选择与 SharePoint 列表中日期的确切日期，它可以计算总天数 = 2 ，这意味着不计算其他天。

有人可以帮忙吗？

我使用以下代码计算总天数的差异，而不计算周末。但我无法弄清楚如何计算所选日期的总天数而不计算其他天数。

function workingDaysBetweenDates(startDate,endDate) {

// Validate input
if (endDate < startDate)
    return 'Invalid !';

// Calculate days between dates
var millisecondsPerDay = 86400 * 1000; // Day in milliseconds
startDate.setHours(0,0,0,1);  // Start just after midnight
endDate.setHours(23,59,59,999);  // End just before midnight
var diff = endDate - startDate;  // Milliseconds between datetime objects    
var days = Math.ceil(diff / millisecondsPerDay);

// Subtract two weekend days for every week in between
var weeks = Math.floor(days / 7);
var days = days - (weeks * 2);

// Handle special cases
var startDay = startDate.getDay();
var endDay = endDate.getDay();

// Remove weekend not previously removed.   
if (startDay - endDay > 1)         
    days = days - 2;


// Remove start day if span starts on Sunday but ends before Saturday
if (startDay == 0 && endDay != 6)
    days = days - 1; 

// Remove end day if span ends on Saturday but starts after Sunday
if (endDay == 6 && startDay != 0)
    days = days - 1;

return days;

}

【问题讨论】：

标签： javascript date sharepoint sharepoint-designer

【解决方案1】：

以下函数计算两个日期之间的工作日数

function getBusinessDatesCount(startDate, endDate) {
    var count = 0;
    var curDate = startDate;
    while (curDate <= endDate) {
        var dayOfWeek = curDate.getDay();
        if(!((dayOfWeek == 6) || (dayOfWeek == 0)))
           count++;
        curDate.setDate(curDate.getDate() + 1);
    }
    return count;
}


//Usage

var startDate = new Date('7/16/2015');
var endDate = new Date('7/20/2015');
var numOfDates = getBusinessDatesCount(startDate,endDate);
$('div#result').text(numOfDates);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="result"/>

【讨论】：

根据w3schools.com/jsref/jsref_obj_date.aspgetDate() 返回月份的日期。这是你的意图吗？
当时间从夏季时间更改为冬季时间时，此操作会失败。例如。 startDate 10/27/17 和 endDate 10/30/17。这将只计算 1 天而不是 2 天。

【解决方案2】：

首先你必须计算时间差，然后将时间转换为天数

var calculateDifference = function(date1, date2){
    var timeDifference = Math.abs(date2.getTime() - date1.getTime());
    return Math.ceil(timeDifference / (1000 * 3600 * 24));//ms * seconds * hours
}

var difference = calculateDifference(new Date("7/16/2015"), new Date("7/20/2015"));

未经测试，但应该可以工作...

【讨论】：

【解决方案3】：

使用momentstartDate和endDate：

function getBusinessDaysCount(startDate, endDate) {
  let relativeDaySequence = [...Array(endDate.diff(startDate, "days")).keys()];
  let daySequence = relativeDaySequence.map(relativeDay => {
    let startDateClone = startDate.clone();
    return startDateClone.add(relativeDay, "days");
  });
  return daySequence.reduce(
    (dayCount, currentDay) => dayCount + (currentDay.day() === 0 || currentDay.day() === 6 ? 0 : 1),
    0
  );
}

【讨论】：

【解决方案4】：

可以试试这个也行。

//fromDate is start date and toDate is end Date
    var timeDiff = Math.abs(toDate.getTime() - fromDate.getTime());
    var diffDays = Math.ceil(timeDiff / (1000 * 3600 * 24)) ;
//  var startDay = fromDate.getDay();
    debugger;
    var diffDayWeek = diffDays + fromDate.getDay();
    var diffDiv = Math.floor(parseInt(diffDayWeek/7));
    diffDiv *= 2; "Saturday and Sunday are Weekend
    diffDays += 1 - diffDiv;

【讨论】：