【发布时间】:2014-10-14 22:48:11
【问题描述】:
我确实看过Accessing ArrayList<ArrayList<SomeObject>> elements,但我认为在我的情况下有一个更简单的答案。还查看了Why does Java ArrayList use per-element casting instead of per-array casting?,这似乎解释了潜在的演员问题,但并不能帮助我了解这里的最佳方法。感谢您抽出宝贵时间阅读本文!
最终,我是一名 Java 新手,只是想实现一个 Map 类,该类将基于文本的 2-d 映射读取到某些数据结构中。因为我在阅读之前不知道地图大小,所以我尝试了 Vectors,但移到了 ArrayLists。
编辑这里的“地图”
12 12
MwwwppppffffMMMM
MMwwppppfffffMMM
MMMwwwwwppppffff
ffffMMMMMwwwpppp
ffffMMMMMwwwpppM
MwwwppfMMMMppfff
MwwwpffffMMMMppp
MwwwppppffffMMMM
wwppppffffMMMMMw
wppppffffMMMMMww
ppppffffMMMMMwww
pppffffMMMMMwwwp
我在方法之外有这个,就在类声明下:
// we have this vector here to be accessible to all methods
// the inner vector will be built in the readMapFile method
static private ArrayList mapList = new ArrayList();
然后在我有的readMapFile方法中(整个方法在最后):
for ( int i = 0; i < mapRows ; ++i)
{
// read each subsequent line in the file
mapFileLine = fileIn.nextLine();
ArrayList mapRowList = new ArrayList();
for ( int j = 0 ; j < mapCols ; ++j )
{
// read each character on the line
mapRowList.add(mapFileLine.charAt(j));
}
// now put mapRowVector as an element of mapVector
mapList.add(mapRowList);
System.out.println(mapList.get(i));
}
然后我在尝试访问内部 ArrayList 中的元素时遇到了麻烦。有了这个我得到“对象不能被转换成 ArrayList:
public static char getTerrainAtLocation( int row, int column )
{
ArrayList innerList = mapList.get(row);
return innerList[column];
}
在我尝试运行它之前不会出错:
public static char getTerrainAtLocation( int row, int column )
{
char[] innerList = (char[])mapList.get(row);
return innerList[column];
}
我显然需要一些帮助!您在这里最好的建议是什么,我只想从“地图”中返回 x 行和 y 列的字符。我收到此错误:
Exception in thread "main" java.lang.ClassCastException: java.util.ArrayList cannot be cast to [C
at adventure2.Map.getTerrainAtLocation(Map.java:144)
at adventure2.Map.printMapList(Map.java:154)
at adventure2.Map.main(Map.java:56)
Java Result: 1
这是我完整的 readMapFile:
public static void readMapFile( String arg )
{
if ( arg != "")
{
try
{
// open a path to the file given in arg 0, this won't throw
// an exception
Scanner fileIn = new Scanner(Paths.get(arg));
// need to clear mapVector for the new file, if it already
// has data in it
mapList.clear();
// this is the line that will throw the exception
// try to read the file, see if it throws IOException
mapRows = fileIn.nextInt();
mapCols = fileIn.nextInt();
// read to the end of line
String mapFileLine = fileIn.nextLine();
// now we have the first line read, with rows and columns
// need a 2-D char array to hold the map
//char[][] mapArray = new char [mapRows][mapCols];
// make up the row vectors row by row, when a row is complete,
// add that to the full Vector, making a Vector of Vectors
for ( int i = 0; i < mapRows ; ++i)
{
// read each subsequent line in the file
mapFileLine = fileIn.nextLine();
ArrayList mapRowList = new ArrayList();
for ( int j = 0 ; j < mapCols ; ++j )
{
// read each character on the line
mapRowList.add(mapFileLine.charAt(j));
}
// now put mapRowVector as an element of mapVector
mapList.add(mapRowList);
System.out.println(mapList.get(i));
}
}
catch ( IOException e )
{
System.out.println("There was an error reading the file sorry!");
}
}
else
{
// arg length was 0 or negative
System.out.println("Must call readMapFile with a filename as argument");
}
} // end readMapFile
谢谢!
【问题讨论】:
-
FWIW 我把地图文字放在上面
-
你到处都在使用原始类型,你应该使用类型参数。
-
八月,我几乎不明白,你指的是调用ArrayList模板时会发生什么?我知道一些 C++,但对 Java 很陌生。
-
1) 带有泛型的原始类型每次都会把你引向这个兔子洞。具体输入您的
ArrayList。 2) 你是在尝试ArrayList<ArrayList<Character>>吗? -
mapList.get(row)不返回ArrayList。它返回存储在该索引处的ArrayList的元素。
标签: java arrays arraylist casting