如何使用 HTTP-GET 连接输入用户名和密码来访问 API答案

【问题标题】：How to use HTTP-GET connect with input username and password for access API如何使用 HTTP-GET 连接输入用户名和密码来访问 API
【发布时间】：2014-02-23 11:11:24
【问题描述】：

我使用 API 获取连接信息，但我无法从此 API 获取数据，因为我不知道如何使用 HTTP 获取连接并输入用户名和密码来访问此数据。

主要

String url = "http://flightxml.flightaware.com/json/FlightXML2/";
    @SuppressLint("NewApi")
    @Override
    protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    StrictMode.ThreadPolicy policy = new StrictMode.
    ThreadPolicy.Builder().permitAll().build();
    StrictMode.setThreadPolicy(policy); 

    TextView txt1 = (TextView)findViewById(R.id.textView1);

    String result  = HttpGet(url);
    txt1.setText(result);
                   }
    // Connect Http Get //
    public String HttpGet(String url) {
    StringBuilder builder = new StringBuilder();
    HttpClient client = new DefaultHttpClient();
    HttpGet httpGet = new HttpGet(url);

    try {
    HttpResponse response = client.execute(httpGet);
    StatusLine statusLine = response.getStatusLine();
    int statusCode = statusLine.getStatusCode();
    if (statusCode == 200) { // Status OK
    HttpEntity entity = response.getEntity();
    InputStream content = entity.getContent();
    BufferedReader reader = new BufferedReader(new InputStreamReader(content));
    String line;
    while ((line = reader.readLine()) != null) {
    builder.append(line);}
    } else {
    Log.e("Log", "Failed to download result..");
    }
    } catch (ClientProtocolException e) {
    e.printStackTrace();
    } catch (IOException e) {
    e.printStackTrace();
    }
    return builder.toString(); }}

在浏览器中我可以输入用户名和密码，但在 Android 应用程序中我不知道如何输入。和这张照片一样。

http://i.stack.imgur.com/63EBI.jpg

【问题讨论】：

您可以直接将用户名和密码传递到字符串中，例如：String url = "http://www.internet.com/api?UserName=YourUsername&Password=yourpassword" 或另一种方式是将用户名和密码传递到 Headers 中，例如：request.addHeader("UserName", username); request.addHeader("Password", password);

标签： java android http http-get

【解决方案1】：

假设您的目标 API 需要基本身份验证，您需要将凭据添加到请求中，如下所示：

String user = "username";
String pwd = "password";
httpGet.addHeader("Authorization", "Basic " + Base64.encodeToString((user + ":" + pwd).getBytes(), Base64.NO_WRAP));

【讨论】：

我在我的 MySQL 数据库前面设置了一个基本的sandman REST API，并且在终端中执行curl http://user:pwd@myserver.com 可以工作，但不能在我的 Android 应用程序中工作。这个答案帮助了我。谢谢！
你需要导入 => import org.apache.commons.codec.binary.Base64

【解决方案2】：

提示，请使用 AsyncTask 而不是停用 StrictMode。

【讨论】：

【解决方案3】：

尝试将您的凭据传递给设置您的credential provider 的HTTP 客户端，并指定您要使用它们just for that server：

String url = "http://flightxml.flightaware.com/json/FlightXML2/";
@SuppressLint("NewApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
StrictMode.ThreadPolicy policy = new StrictMode.
ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy); 

TextView txt1 = (TextView)findViewById(R.id.textView1);

String result  = HttpGet(url);
txt1.setText(result);
               }

// Connect Http Get //
public String HttpGet(String url) {
StringBuilder builder = new StringBuilder();
HttpClient client = new DefaultHttpClient();

// Set up the credential provider for that server and port
CredentialsProvider credentials = new BasicCredentialsProvider();
credProvider.setCredentials(new AuthScope("flightxml.flightaware.com", 80),
    new UsernamePasswordCredentials("username", "password"));

// and tell your client to use it
client.setCredentialsProvider(credentials);

// then fetch your data
HttpGet httpGet = new HttpGet(url);

try {
HttpResponse response = client.execute(httpGet);
StatusLine statusLine = response.getStatusLine();
int statusCode = statusLine.getStatusCode();
if (statusCode == 200) { // Status OK
HttpEntity entity = response.getEntity();
InputStream content = entity.getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(content));
String line;
while ((line = reader.readLine()) != null) {
builder.append(line);}
} else {
Log.e("Log", "Failed to download result..");
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return builder.toString(); }}

【讨论】：