【发布时间】:2012-03-21 16:58:43
【问题描述】:
我从 HttpGet 获取字符串,我想将它们放入列表视图中。我怎么能这样做?我在任何地方都找不到关于它的任何信息。在运动中,我只有一些测试数据。
例如。
“测试1”
但我希望它是动态的,从电话从 HttpGet 获取的字符串。
谢谢。
到目前为止我的代码:(对于代码混乱,我会尽快重写它!)
public class ChatService extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.chatservice);
try {
ContactsandIm();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (URISyntaxException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
CheckLogin();
ListView list = (ListView) findViewById(R.id.ListView01);
list.setClickable(true);
final List<PhoneBook> listOfPhonebook = new ArrayList<PhoneBook>();
listOfPhonebook.add(new PhoneBook("a", "9981728", "test@test.com"));
listOfPhonebook
.add(new PhoneBook("Test1", "1234455", "test1@test.com"));
listOfPhonebook.add(new PhoneBook("Test2", "00000", "test2@test.com"));
PhonebookAdapter adapter = new PhonebookAdapter(this, listOfPhonebook);
list.setOnItemClickListener(new OnItemClickListener() {
public void onItemClick(AdapterView<?> arg0, View view,
int position, long index) {
System.out.println("sadsfsf");
showToast(listOfPhonebook.get(position).getName());
}
});
list.setAdapter(adapter);
}
private void CheckLogin() {
// TODO Auto-generated method stub
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
/* login.php returns true if username and password is equal to saranga */
HttpPost httppost = new HttpPost("http://gta5news.com/login.php");
try {
// Execute HTTP Post Request
Log.w("HttpPost", "Execute HTTP Post Request");
HttpResponse response = httpclient.execute(httppost);
String str = inputStreamToString(response.getEntity().getContent())
.toString();
Log.w("HttpPost", str);
if (str.toString().equalsIgnoreCase("true")) {
Log.w("HttpPost", "TRUE");
try {Thread.sleep(250);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
//put intent here(21/3/12);
} else {
Log.w("HttpPost", "FALSE");
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
private StringBuilder inputStreamToString(InputStream is) {
String line = "";
StringBuilder total = new StringBuilder();
// Wrap a BufferedReader around the InputStream
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
// Read response until the end
try {
while ((line = rd.readLine()) != null) {
total.append(line);
}
} catch (IOException e) {
e.printStackTrace();
}
// Return full string
return total;
}
private void ContactsandIm() throws URISyntaxException, ClientProtocolException, IOException {
// TODO Auto-generated method stub
BufferedReader in = null;
String data = null;
HttpClient get = new DefaultHttpClient();
URI website = new URI("http://www.gta5news.com/test.php");
HttpGet webget = new HttpGet();
webget.setURI(website);
HttpResponse response = get.execute(webget);
Log.w("HttpPost", "Execute HTTP Post Request");
in = new BufferedReader (new InputStreamReader(response.getEntity().getContent()));
//now we'll return the data that the PHP set from the MySQL Database.
// just some test code, to see if the HttpGet was working.
if (in.equals("True")); {
Toast.makeText(this,"yay", Toast.LENGTH_LONG).show();
}
}
// end bracket for "ContactsandIm"
private void showToast(String message) {
Toast.makeText(this, message, Toast.LENGTH_LONG).show();
}
}
【问题讨论】:
-
那是什么?我以前从未见过这种方法。
标签: java android http listview http-get