【问题标题】:Why am I getting a http 500 response?为什么我收到 http 500 响应?
【发布时间】:2019-03-28 21:29:15
【问题描述】:

我正在尝试通过对路径参数使用“ID”来检索数据库中的值。但是,在尝试检索这些值时,我在 URi(http://localhost:8080/JAX_RS/rest/details/123) 中收到了 HTTP 500 响应。下面是我的 DAO 课程。如果需要,我还可以提供我的资源类。对于任何反馈,我们都表示感谢。

DetailsDAO


package dao;

import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.util.ArrayList;
import java.util.List;
import java.util.logging.Level;
import java.util.logging.Logger;

public class DetailsDAO {

    private Connection con = null;

    public DetailsDAO() {
        try {
            System.out.println("Loading db driver...");
            //Class.forName("org.apache.derby.jdbc.ClientDriver");
            System.out.println("Driver loaded...");
            con = DriverManager.getConnection(
                    "jdbc:derby://localhost:1527/SOA4_DB",
                    "sean",
                    "sean");
        } catch (SQLException ex) {
            System.out.println("Exception!");
            ex.printStackTrace();

        }
    }

    public static void main(String[] args) {
        DetailsDAO dao = new DetailsDAO(); // connect to db
        List<Details> detailsList = dao.getAllDetails();
        for (Details d : detailsList) {
            System.out.println(d);
        }
    }
    public List<Details> getAllDetails() {
        List<Details> detailsList = new ArrayList<>();

        try {
            // SQL in here
            PreparedStatement ps = con.prepareStatement(
                    "SELECT * FROM APP.DETAILS"
            );
            ResultSet rs = ps.executeQuery();
            while (rs.next()) {
                Details d = new Details
                        (rs.getInt("ID"),
                        rs.getString("NAME"),
                        rs.getInt("AGE"),
                        rs.getTimestamp("TIMESTAMP"));
                detailsList.add(d);
            }
        } catch (SQLException ex) {
            System.err.println("\nSQLException");
            ex.printStackTrace();
        }

        return detailsList;
    }

    public Details getDetails(int id){
        Details details = null;

        try{
            // SQL in here  
            PreparedStatement pstmt = con.prepareStatement(
                    "SELECT ID, NAME, AGE, TIMESTAMP, "
                            + "FROM APP.DETAILS "
                            + "WHERE (ID = ?)");
            pstmt.setInt(1, id);

            ResultSet rs = pstmt.executeQuery();

            // move the cursor to the start
            if(!rs.next()){ // !F == T
                return null;
            }

            // we have at least one record
            details = new Details
                        (rs.getInt("ID"),
                        rs.getString("NAME"),
                        rs.getInt("AGE"),
                        rs.getTimestamp("TIMESTAMP"));

        } catch (SQLException ex) {
            Logger.getLogger(DetailsDAO.class.getName()).log(Level.SEVERE, null, ex);
            System.err.println("\nSQLException");
            ex.printStackTrace();
        }

        return details;
    }
}

【问题讨论】:

  • 服务器上是否生成了异常和/或堆栈跟踪?
  • @NotaJD 异常 javax.servlet.ServletException: java.lang.NullPointerException 根本原因 java.lang.NullPointerException

标签: java http get localhost derby


【解决方案1】:

查询中TIMESTAMP 后面有多余的逗号

PreparedStatement pstmt = con.prepareStatement(
                "SELECT ID, NAME, AGE, TIMESTAMP, "
                        + "FROM APP.DETAILS "
                        + "WHERE (ID = ?)");

【讨论】:

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