我可以使用 GsonConverterFactory 将 JSON 转换为 HashMap 吗？

Question

我使用 Retrofit 库获得了这些数据

[
  {
    "countryId": "1472",
    "countryName": "{"ar": "ألمانيا", "default": "Germany"}",
    "image": "a304035c3dcb42cd990bb69b2f03e31f.png"
  },
  {
    "countryId": "1473",
    "countryName": "{"ar": "إيطاليا", "default": "Italy"}",
    "image": "5b3ae479ada846e98309ed978c2707b5.png"
  },
  {
    "countryId": "1474",
    "countryName": "{"ar": "هولندا", "default": "Netherlands"}",
    "image": "d810f9ab22434b4da08b838e72add09d.png"
  },
  {
    "countryId": "1475",
    "countryName": "{"ar": "بولندا", "default": "Poland"}",
    "image": "d8c4de2a11ca45759089fec204af9659.png"
  },
  {
    "countryId": "1476",
    "countryName": "{"ar": "رومانيا", "default": "Romania"}",
    "image": "47efdea8456244a5b9aae7132fca7418.png"
  },
  {
    "countryId": "1477",
    "countryName": "{"ar": "روسيا", "default": "Russia"}",
    "image": "7163f60a1c494e1b9f782edd3ecabd31.png"
  },
  {
    "countryId": "1478",
    "countryName": "{"ar": "إسبانيا", "default": "Spain"}",
    "image": "52fe49f594074b078fd5d8c9625018ee.png"
  },
  {
    "countryId": "1479",
    "countryName": "{"ar": "اوكرانيا", "default": "Ukraine"}",
    "image": "28581f7e4f324d938e0b109f7ee9203e.png"
  },
  {
    "countryId": "1480",
    "countryName": "{"ar": "المملكة المتحدة", "default": "United Kingdom"}",
    "image": "e7a87ff0caa241559f6c2559cc8606c3.png"
  },
  {
    "countryId": "2147483647",
    "countryName": "{"ar": "فرنسا", "default": "France"}",
    "image": "3830917201c74fc9b6b4ed0ddfdd4866.png"
  }
]

这是获取数据的代码

Retrofit retrofit = new Retrofit.Builder().baseUrl(Constants.baseURL).addConverterFactory(GsonConverterFactory.create()).build();
TestInterface testInterface = retrofit.create(TestInterface.class);
testInterface.getCountries().enqueue(new Callback < List < CountriesModel >> () {
    @Override
    public void onResponse(@NonNull Call < List < CountriesModel >> call, @NonNull Response < List < CountriesModel >> response) {
        if (response.body() == null)
            return;
        for (CountriesModel item: response.body()) {
            Chip chip = new Chip(requireActivity());
            chip.setText(item.getCountryName());
            fragmentSelectCountryBinding.fragmentSelectCountryChipGroup281.addView(chip);
        }
    }

    @Override
    public void onFailure(@NonNull Call < List < CountriesModel >> call, @NonNull Throwable t) {
        Log.w(Tag, "Failed - " + t.getMessage());
    }
});

测试接口

public interface TestInterface {

    @GET("FetchCountries.php")
    Call<List<CountriesModel>> getCountries();

}

CountriesModel 类

public class CountriesModel {

    @SerializedName("countryId")
    private long countryId;

    @SerializedName("countryName")
    private String countryName;

    @SerializedName("image")
    private String image;

    public long getCountryId() {
        return countryId;
    }

    public String getCountryName() {
        return countryName;
    }

    public String getImage() {
        return image;
    }

}

MySQL 中的列

国家名称显示在芯片中像这样{"ar": "ألمانيا", "default": "Germany"}, {"ar": "إيطاليا", "default": "Italy"}, {"ar": "هولندا", "default": "Netherlands"}, etc...

国家名称中的JSON，我可以将它存储在HashMap中并根据下面的键获取值吗？

chip.setText(item.getCountryName().get("default"));

我可以使用GsonConverterFactory 做这样的事情吗？

编辑

This answer 与我想要的很接近，但我想在同一个模型中执行此操作而不创建两个模型。

Answer 1

也许你可以，但我不确定你是否应该。您的问题似乎是国家名称实际上是“内部”JSON。我猜它实际上是像下面这样转义的，否则它将无法解析：

[
 {
    "countryId": "1476",
    "countryName": "{\"ar\": \"رومانيا\", \"default\": \"Romania\"}",
    "image": "47efdea8456244a5b9aae7132fca7418.png"
  }
]

可以为 countryName 创建一个自己的类，并使用一个自定义反序列化器来处理这个“内部”JSON。请参见下面的示例（不需要是静态内部类，但为简洁起见）：

@Getter @Setter
public class CountriesModel {
    private long countryId;
    // define representation for complex name
    @Getter @Setter
    public static class CountryName {
        // define a custom deserializer for "inner" JSON
        public static class CountryNameDeserializer
                implements JsonDeserializer<CountryName> {
            private final Gson gson = new Gson();
            @Override
            public CountryName deserialize(JsonElement json, Type typeOfT,
                                                JsonDeserializationContext context)
                    throws JsonParseException {
                // gets the field as string and parses it again as a CountryName object
                return gson.fromJson(json.getAsString(), CountryName.class);
            }
        } 
        private String ar;
        // default is a reserved word
        @SerializedName("default")
        private String defaultName;
    }
    // Use the adapter
    @JsonAdapter(CountryNameDeserializer.class)
    private CountryName countryName;
    private String image;
}

现在它就像：

someCountriesModel.getCountryName().getDefaultName();