如何通过选择查询复制和合并行

Question

我有一个现有的 Postgresql 选择查询输出给我，

+------+------------+------+------+
| Type | ID         | Pass | Fail |
+------+------------+------+------+
| IQC  | ABC_IQC_R2 | 0    | 6    |
+------+------------+------+------+
| IQC  | ABC_IQC_R1 | 2    | 6    |
+------+------------+------+------+
| IQC  | ABC_IQC    | 498  | 8    |
+------+------------+------+------+

如何将 ID-> ABC_IQC 行复制为两行，同时将 R1 和 R2 值合并到该行中？ （如下图）

+------+---------+------------+------+------+--------+--------+
| Type | ID      | R_ID       | Pass | Fail | R_Pass | R_Fail |
+------+---------+------------+------+------+--------+--------+
| IQC  | ABC_IQC | ABC_IQC_R2 | 498  | 8    | 0      | 6      |
+------+---------+------------+------+------+--------+--------+
| IQC  | ABC_IQC | ABC_IQC_R1 | 498  | 8    | 2      | 6      |
+------+---------+------------+------+------+--------+--------+

我能想到的两个逻辑是，

1. 遍历 ID 以搜索 ABC（但我不确定如何匹配它们）。复制 ABC_IQC 行，然后使用横向连接合并它们（仍然不确定如何）

2. 从 R2 和 R1（现在成为 R_ID）复制 ABC_IQC（ID 列）的列。搜索原始 ABC_IQC 行的 ID，并将通过和失败的值提取到 R2 和 R1 行中。

这是我当前获取初始查询输出的查询，

SELECT
  split_part(NewLotID, '_', 2) AS "Type",
  LotSummary ->> 'ID' AS "ID",
  LotSummary ->> 'Pass' AS "Pass",
  LotSummary ->> 'Fail' AS "Fail"
FROM
(
  SELECT
    LotSummary,
    regexp_replace(LotSummary ->> 'ID','[- ]','_','g') AS NewLotID
.
.
.

我并不期待完整的答案，因为我几乎没有提供任何代码，只是提供任何可能有用的想法或见解！提前谢谢你。

Answer 1

我想你想要join:

with q as (
      <your query here>
     )
select q.type, q.id, qr.id as r_id, q.pass, q.fail,
       qr.pass as r_pass, qr.fail as r_fail
from q join
     q qr
     on q.id = 'ABC_IQC' and qr.id like 'ABC_IQC_%';

您实际上可以概括这一点：

with q as (
      <your query here>
     )
select q.type, q.id, qr.id as r_id, q.pass, q.fail,
       qr.pass as r_pass, qr.fail as r_fail
from q join
     q qr
     on q.id ~ '^[^_]+_[^_]+$' and
        qr.id like q.id || '_%';