嗨,
我认为你必须像这样添加一个 as.character:
sapply(sequence.to_roman, function(x) as.character(if(grepl("^[1-9]\\d*$",x)) as.roman(x) else "Some symbols"))
> sapply(sequence.to_roman, function(x) as.character(if(grepl("^[1-9]\\d*$",x)) as.roman(x) else "Some symbols"))
1 2 V1 df 3
"I" "II" "Some symbols" "Some symbols" "III"
默认情况下,sapply 中输出的缩短似乎会将 roman 类转换回其数值。因此,首先将所有输出转换为 char 可以防止这种情况。
试试:
lapply(sequence.to_roman, function(x) if(grepl("^[1-9]\\d*$",x)) as.roman(x) else "Some symbols")
> lapply(sequence.to_roman, function(x) if(grepl("^[1-9]\\d*$",x)) as.roman(x) else "Some symbols")
[[1]]
[1] I
[[2]]
[1] II
[[3]]
[1] "Some symbols"
[[4]]
[1] "Some symbols"
[[5]]
[1] III
这就是我们想要的,但是:
unlist(lapply(sequence.to_roman, function(x) if(grepl("^[1-9]\\d*$",x)) as.roman(x) else "Some symbols"))
> unlist(lapply(sequence.to_roman, function(x) if(grepl("^[1-9]\\d*$",x)) as.roman(x) else "Some symbols"))
[1] "1" "2" "Some symbols" "Some symbols" "3"
还给出了recodet表格。
对于导致问题的可能更明显的描述:
> as.roman("3")
[1] III
> as.character(as.roman("3"))
[1] "III"
> c(as.roman("3"), "test")
[1] "3" "test"
> c(as.character(as.roman("3")), "test")
[1] "III" "test"