【发布时间】:2018-01-15 16:30:06
【问题描述】:
我目前正在制作一个 Windows 表单登录系统,我已经研究了如何设置一个普通的每个人都可以看到主页系统,但对于管理员我希望它打开一个新表单 (form3),其中包含客户订单。 我需要它从登录按钮打开。单击就像打开 form2 以显示一般用户的商店页面。我的表中也没有用于用户角色的列。 我已经尝试过 if else 语句并遇到了 bools 的问题,但字符串等除外。
using System;
using System.Data;
using System.Windows.Forms;
using MySql.Data;
using MySql.Data.MySqlClient;
namespace Aliena_Store
{
public partial class Form1 : Form
{
//string ConnectionState = "";
public Form1()
{
InitializeComponent();
}
MySqlConnection connection = new MySqlConnection("server=localhost;user=root;database=Aliena_Store;port=3306;password=Blackie");
MySqlDataAdapter adapter;
DataTable table = new DataTable();
private void UsernameLogin_TextChanged(object sender, EventArgs e)
{
}
private void PasswordLogin_TextChanged(object sender, EventArgs e)
{
}
private void LoginButton_Click(object sender, EventArgs e)
{
adapter = new MySqlDataAdapter("SELECT `username`, `password` FROM `User_Details` WHERE `username` = '" + UsernameLogin.Text + "' AND `password` = '" + PasswordLogin.Text + "'", connection);
adapter.Fill(table);
var usernameSaved = UsernameLogin.Text;
var passwordSaved = PasswordLogin.Text;
Panel panel1 = new Panel();
if (table.Rows.Count <= 0)
{
panel1.Height = 0;
var result = MessageBox.Show("Username/Password Are Invalid or does not exist. Please sign up or retry your details");
}
else
{
panel1.Height = 0;
this.Hide();
if (table.Rows.Count >= 0)
{
Form nextForm;
var result = MessageBox.Show("Login successful...Now logging in");
this.Hide();
object user = UsernameLogin.Text;
object password = PasswordLogin.Text;
if (user = "root" & password = "Pa$$w0rd")
{
nextForm = new Form3();
}
else
{
nextForm = new Form2();
}
nextForm.ShowDialog();
}
//Form2 f2 = new Form2();
//f2.ShowDialog();
//if login is successful needs to lead to another screen - if matches my account standard store screen or make root account just for the admin page
}
table.Clear();
}
private void EmailSignUp_TextChanged(object sender, EventArgs e)
{
}
private void UsernameSignUp_TextChanged(object sender, EventArgs e)
{
}
private void PasswordSignUp_TextChanged(object sender, EventArgs e)
{
}
private void SignUpButton_Click(object sender, EventArgs e)
{
//connection.Open();
string Query = "insert into User_Details (Email,Username,Password) values('" + this.EmailSignUp.Text + "', '" + this.UsernameSignUp.Text + "','" + this.PasswordSignUp.Text + "');";
//string insertQuery = "INSERT INTO User_Details(Email,Username,Password)VALUES('" + EmailSignUp.Text + "','" + UsernameSignUp.Text + "'," + PasswordSignUp.Text + ")";
MySqlCommand command = new MySqlCommand(Query,connection);
try
{
if (command.ExecuteNonQuery() == 1)
{
MessageBox.Show("Data Inserted");
connection.Close();
}
else
{
MessageBox.Show("Data Not Inserted");
}
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
connection.Close();
}
}
}
}
【问题讨论】:
-
“我尝试了几种方法都没有成功,目前无法启动和运行” 不是问题描述。 什么你试过了吗? 什么有问题吗?不要指望读者会通灵或浪费时间提出您已经反驳的事情。
标签: c# mysql visual-studio login-control