在 CakePHP 3 中加入 SQL 函数

Question

您好，我想将此查询更改为 cakePHP 3.0 格式，但代码无法正常工作，你们能帮我解决这个问题吗？

普通 SQL：

SELECT COUNT(user_tag_review.id) AS user_numbers, SUM(user_rating.rating_value) AS rating_value FROM user_tag_review INNER JOIN user_rating ON user_tag_review.id = user_rating.review_id WHERE user_tag_review.recruiter_id = 2 AND user_rating.rating_id = 1

我用过的CakePHP代码：

$review_table = TableRegistry::get('UserTagReview');
        $query = $review_table->find();
        $query->select(["user_numbers" => $query->func()->count("UserTagReview.id")])
                ->hydrate(false)
                ->join(["table" => "user_rating",
                    "alias" => "r",
                    "type" => "INNER",
                    "condition" => ['r.review_id = UserTagReview.id']
                ])
                ->select(["rating_value" => $query->func()->sum("r.rating_value")])
                ->where(["UserTagReview.recruiter_id" => $recruiter_id, "UserTagReview.rating_id = " . 1]);

        $result = $query->all()->toArray();

Answer 1

我认为将 SQL 迁移到 Cake 的更简单方法是 fields finder 中的选项：

$table = TableRegistry::get('UserTagReview');

$result = $table
    ->find('all' , [
        'fields' => [
            'user_numbers' => 'COUNT(UserTagReview.id)', 
            'rating_value' => 'SUM(user_rating.rating_value)'
        ], 
        'join' => [
            [
                'table' => 'user_rating', 
                'alias' => 'user_rating', 
                'type' => 'INNER', 
                'conditions' => [
                    'UserTagReview.id = user_rating.review_id'
                ]
            ]
        ], 
        'conditions' => [
            'UserTagReview.recruiter_id' => 2, 
            'user_rating.rating_id' => 1

        ]
    ])
->hydrate(FALSE)
->toArray();

也许这段代码不是 100% 正确，但关注fields 数组——如果我们使用它作为关联数组，我们可以评估任何 sql：

'fields' => [
    'alias' => 'COUNT(IF(1,1,0))'
]