CakePHP 3 在连接表中保存额外数据

Question

$this->request-data 的数据需要修改，所以我不能直接使用表单来填充所有表格。在我添加“状态”列之前，所有代码都已烘焙。

order_id    int(11) PK
part_id int(11) PK
state   varchar(10)

我从 $this->request-data 获取 id 并进行相应修改：

$this->request->data['parts']['_ids'][]=....

其余的按照手册进行：

$order = $this->Orders->newEntity();
$this->Orders->patchEntity($order, $this->request->data);
$this->Orders->save($order);

我无法修改传入数据以将其保存到状态列

编辑：

“状态”字段仍为空值。

订单表

public function initialize(array $config)
{
    parent::initialize($config);

    $this->table('orders');
    $this->displayField('id');
    $this->primaryKey('id');

    $this->addBehavior('Timestamp');

    $this->belongsTo('Users', [
        'foreignKey' => 'user_id',
        'joinType' => 'INNER',
    ]);
    $this->belongsToMany('Parts', [
        'foreignKey' => 'order_id',
        'targetForeignKey' => 'part_id',
        'joinTable' => 'orders_parts',
        'through' => 'OrdersParts',

    ]);
    $this->belongsToMany('Sets', [
        'foreignKey' => 'order_id',
        'targetForeignKey' => 'set_id',
        'joinTable' => 'orders_sets',
    ]);
}

订单表

public function initialize(array $config)
{
    parent::initialize($config);

    $this->table('parts');
    $this->displayField('name');
    $this->primaryKey('id');

    $this->addBehavior('Timestamp');


    $this->belongsTo('Orders', [
        'foreignKey' => 'order_id',
        'joinType' => 'INNER',
    ]);

    $this->belongsToMany('Orders', [
        'foreignKey' => 'part_id',
        'targetForeignKey' => 'order_id',
        'joinTable' => 'orders_parts',

    ]);

    $this->belongsToMany('States', [
        'foreignKey' => 'part_id',
        'targetForeignKey' => 'state_id',
        'joinTable' => 'parts_states'
    ]);
}

插入：

$order = $this->Orders->newEntity();
$order->status = 'new';
$order->user_id = $this->Auth->user('id');
$this->request->data['parts'][0]['_joinData']['state'] = "whatever";
$this->Orders->patchEntity(
$order,
$this->request->data,
['associated' => ['Sets','Parts._joinData']]
);

$this->Orders->save(
$order,
['associated' => ['Sets','Parts._joinData']]
);

我必须将 SetsModel 也包含到关联中。

Answer 1

$this->request->data['parts']['_ids'] 允许您连接表，但不能以这种方式添加数据。 为此，您的 $this->request->data['parts'] 结构必须如下所示：

'parts' => [
    0 => [
        'id'=> 1,
        '_joinData' => [
            'state' => 'exampleSate'
        ]
    ]
]

确保您的“parts”数组中不再有“_ids”数组，否则您将无法将数据保存到连接表中。
'id' 字段对应于相关部分的 id。设置它：

$this->request->data['parts'][0]['id'] = <idOfTheConcernedPart>;

要设置您的“状态”字段，只需执行以下操作：

$this->request->data['parts'][0]['_joinData']['state'] = "whatever";

最后你需要告诉 cakephp 你正在保存一些 _joinData 通过添加一些配置到你的 patchEntity 和 save 方法：

$this->Orders->patchEntity(
    $order, 
    $this->request->data, 
    ['associated' => ['Parts._joinData']]
);

$this->Orders->save(
    $order, 
    ['associated' => ['Parts._joinData']]
);

希望对你有帮助
干杯。