【问题标题】:gradle windows java.io.IOException: CreateProcess error=206, filename is too longgradle windows java.io.IOException: CreateProcess error=206, 文件名太长
【发布时间】:2018-06-05 18:53:53
【问题描述】:

针对 gradle 的 windows 路径太长的问题有几个解决方案:

但是,我不清楚如何在多项目设置中处理此问题。所有带有application 插件的子项目都需要这些更改吗? 这也可以在init.gradle 文件中指定吗?

还有更好的解决方法吗?

显然https://github.com/viswaramamoorthy/gradle-util-plugins/ 已发布。但是,它并不能解决我的问题。最初的 java 问题已解决 - 但不正确。某些类无法再加载,即在 scala 的情况下执行单元测试。

编辑

experimenting with
task testPathingJar(type: Jar) {
        appendix = "testPathing"
        doFirst {
            manifest {
            attributes "Class-Path": configurations.testCompile.files.join(" ")
            }
        }
    }

    compileTestScala {
        dependsOn(testPathingJar)
        classpath = files(testPathingJar.archivePath)
    }    

    task pathingJar(type: Jar) {
        appendix = "pathing"
        doFirst {
            manifest {
            attributes "Class-Path": configurations.compile.files.join(" ")
            }
        }
    }

    compileScala {
        dependsOn(pathingJar)
        classpath = files(pathingJar.archivePath)
    }    

    build {
        dependsOn pathingJar
        doFirst {
            classpath = files("$buildDir/classes/main", "$buildDir/resources/main", pathingJar.archivePath)
        }
    }

不幸的是,在 shadowJar 期间失败了,因为在几个链接中报告的清单技巧似乎与 scala 有问题:

Cannot infer Scala class path because no Scala library Jar was found. Does project ':tma-mobility-frequencyCounting' declare dependency to scala-library? Searched classpath: file collection.

尝试:

    jar {
      manifest {
        attributes(
          "Class-Path": configurations.compileOnly.collect { it.getName() }.join(' '))
      }
    }
fails for task `shadowDistZip` when executing `gradle build` with:

    java.io.IOException: Cannot run program "C:\Program Files\Java\jdk1.8.0_131\bin\java.exe" (in directory "D:\users\username\development\projects\projectName\Code\spark\module_name"): CreateProcess error=206, Der Dateiname oder die Erweiterung ist zu lang

moving gradle user home to the root (also the project) of the partition:

    .\gradlew.bat build --gradle-user-home D:\projects\gradleHome
fails with the same error for task `test`.

When trying the strategy of https://github.com/jhipster/generator-jhipster/pull/4324/files like:

task pathingJar(type: Jar) {
    dependsOn configurations.runtime
    appendix = 'pathing'

    doFirst {
        manifest {
            attributes 'Class-Path': configurations.runtime.files.collect {
                it.toURL().toString().replaceFirst(/file:\/+/, '/')
            }.join(' ')
        }
    }
}

build {
    dependsOn pathingJar
    doFirst {
        classpath = files("$buildDir/classes/main", "$buildDir/resources/main", pathingJar.archivePath)        }
}

task pathingJarTest(type: Jar) {
    dependsOn configurations.runtime
    appendix = 'pathing'

    doFirst {
        manifest {
            attributes 'Class-Path': configurations.runtime.files.collect {
                it.toURL().toString().replaceFirst(/file:\/+/, '/')
            }.join(' ')
        }
    }
}

test {
    dependsOn pathingJarTest
    doFirst {
        classpath = files("$buildDir/classes/main", "$buildDir/resources/main", pathingJarTest.archivePath)        }
}

失败

Caused by: org.gradle.api.GradleException: There were failing tests. See the report at: file:///C:/tmp/projectName/moduleName/reports/tests/test/index.html

即使这个文件永远不会被创建

再尝试一件事:一个包含所有测试用例的胖罐子:

task fatTestJar(type: Jar) {
    baseName = project.name + '-test-all'
    from {
        from { configurations.testRuntime.collect { it.isDirectory() ? it : zipTree(it) }}
        from sourceSets.test.output
    }
    with jar
}

但是,这还没有编译。

【问题讨论】:

标签: java windows scala gradle cmd


【解决方案1】:
test {
  doFirst {
    def cp = CollectionUtils.join(File.pathSeparator, classpath.getFiles())
    environment 'CLASSPATH', cp
    classpath = classpath.filter { false }
  }
}

来自https://github.com/maiflai/gradle-scalatest/issues/63 是迈向解决方案的下一步。

【讨论】:

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