如何在完全工作的查询中仅返回高于平均值的行？

Question

我有以下查询，它返回一个行列表。每行都有自己的souma 列。实际返回的是 26 行。

我想要实现但不幸的是不能，只显示他们的souma 在这 26 行（不是整个表）中高于avg(souma) 的行。

为此我必须做出哪些改变？

SELECT * 
FROM   (SELECT a.*, 
               page, 
               Count(*) AS total 
        FROM   (SELECT *,
                       Sum(percentile_visits_frequency 
                           + percentile_time_spent + percentile_visits 
                           + percentile_last_visit 
                           + Datediff(last_visit, first_visit)) AS souma, 
                       Datediff(last_visit, first_visit)        AS 
                       diafora_imeron 
                FROM   new_table 
                WHERE  company_id = 1 
                       AND Datediff(last_visit, first_visit) > 0 
                GROUP  BY hash 
                ORDER  BY souma DESC, 
                          diafora_imeron DESC) a 
               JOIN behaviour 
                 ON ( behaviour.hash = a.hash ) 
        GROUP  BY page, 
                  hash 
        ORDER  BY total DESC) dd 
GROUP  BY hash 
ORDER  BY souma DESC

Answer 1

那么你需要一个子查询

 SELECT AVG(souma)
 FROM (SELECT souma
       FROM <yourquery>) as T  --this query is the one returning 26 rows