【发布时间】:2017-03-02 13:29:05
【问题描述】:
我的存储库中有以下本机查询方法:
@Query(value="SELECT appSub.ApplicationFormId as appFormId, appSub.profileId as profileId, "
+ "p.CASId as profileCASId, ps.programId as programId FROM [unicas_config].[dbo].ApplicationFormEarlyDecisionConfig appFormED "
+ "INNER JOIN [unicas_ux].[dbo].ApplicationSubmission appSub ON appFormED.ApplicationFormId = appSub.applicationFormId "
+ "INNER JOIN [unicas_ux].[dbo].Profile p ON appSub.profileId = p.id "
+ "INNER JOIN [unicas_ux].[dbo].ProgramSelected ps ON p.id=ps.ProfileId AND appSub.applicationFormId = ps.instanceId "
+ "WHERE appFormED.EarlyDecisionVerdictDate >=:fromDate AND appFormED.EarlyDecisionVerdictDate <:toDate "
+ "AND appSub.EarlyDecisionStatus='Applied Early Decision' "
+ "AND appSub.ApplicationStatus='Received' "
+ "AND ps.IsPaid =1 "
+ "ORDER BY appSub.ApplicationFormId",nativeQuery = true)
List<Object[]> getAllEarlyDecisionApplicantsWithPaidProgramsOnVerdictDate(@Param("fromDate") Date fromDate, @Param("toDate") Date toDate);
现在,我要映射返回的结果:
long appFormId = (Long)obj[0]
long profileId = (Long)obj[1]
long programId = (Long)obj[3]
当我这样做时,我得到 java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.Long,因为 Hibernate 考虑这些 Integer 类型的 id 而不是 Long。
请告诉我如何以编程方式告诉 Hibernate 返回正确的类型。
【问题讨论】:
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我认为这与 Hibernate 没有太大关系。 JDBC 驱动程序将返回与数据库中的列类型对应的 Java 类型。为什么不能只使用 Java Integer?
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@AlanHay。是的,你赖特。我看到数据库中的列类型是 Int 类型,即使实体 ID 也是 long 类型。这就是为什么我得到 Integer 而不是 long。
标签: java hibernate jpa spring-data-jpa jpa-2.0