PHP 将 JSON 编码为单独的数组

Question

我认为我正在处理的 PHP 页面可能存在语法问题，但尽管测试了多种方法，但我似乎无法破解这个问题。

对于上下文，我有一个页面查询 MySQL 数据库并获取一组部门名称和每个部门的三台服务器（Mac、Windows 和 Linux）的主机名。一旦有了这些数据，它就会调用一个函数，该函数使用这些主机名来获取关于每个服务器的更具体的数据集（比如说通过其他 MySQL 查询、CURL 等），并将每个部门服务器的数据添加到一个数组中。理想情况下，我试图将数组打印为 JSON 数据，但让所有 JSON 数据成为一个主数组的一部分。一切正常，除了 JSON 数据将每个数组分成自己的实体；

{
"department": "Math",
"macOS": "10.10.3",
"macRAM": "64GB",
"windowsOS": "2012.2",
"windowsRAM": "128GB",
"linuxOS": "5.5.1",
"linuxRAM": "32GB",
}
{
"department": "Science",
"macOS": "10.9.5",
"macRAM": "64GB",
"windowsOS": "XP",
"windowsRAM": "128GB",
"linuxOS": "1.2.3",
"linuxRAM": "32GB",
}

如上所述，所呈现的 JSON 数据不是用逗号分隔的，而是嵌入在括号中。我希望；

[
{
"department": "Math",
"macOS": "10.10.3",
"macRAM": "64GB",
"windowsOS": "2012.2",
"windowsRAM": "128GB",
"linuxOS": "5.5.1",
"linuxRAM": "32GB",
},
{
"department": "Science",
"macOS": "10.9.5",
"macRAM": "64GB",
"windowsOS": "XP",
"windowsRAM": "128GB",
"linuxOS": "1.2.3",
"linuxRAM": "32GB",
}
]

对不起，这里是我的 PHP 正在做所有的工作；

<?php
$data = array();
?>

<?php
$conn = mysqli_connect("localhost", "root", "root") or die('Error connecting to MySQLserver.');
mysqli_select_db($conn, "Database") or die("Failed to connect to database");
$sql = "SELECT * FROM Servers";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
    $department = $row['department'];
    $serverMac = $row['serverMac'];
    $serverWindows = $row['serverWindows'];
    $serverLinux = $row['serverLinux'];
    getData($department, $serverMac, $serverWindows, $serverLinux);
}
} else {
echo "Unable to connection to server.  Please check your settings.";
}
?>

<?
function getData($serverMac, $serverWindows, $serverLinux) {

//Gather Data About Server Mac
//do something with the variable $serverMac

//Gather Data About Server Windows
//do something with the variable $serverWindows

//Gather Data About Server Linux
//do something with the variable $serverLinux

//Put The Gathered Data In An Array
$data = array('department' => $department, 
'macOS' => $macOS, 
'macRAM' => $macRAM
'windowsOS' => $windowsOS,
'windowsRAM' => $windowsRAM,
'linuxOS' => $linuxOS,
'linuxRAM' => $linuxRAM);
printData($data);
}
?>

<?php
function printData($data) {
echo "<pre>";
echo json_encode($data, JSON_PRETTY_PRINT);
echo "</pre>";
}
?>

任何帮助将不胜感激！谢谢！

Answer 1

您希望将有关服务器的所有数据存储在一个嵌套的 php 数组中。然后json_encode 会处理剩下的事情。

<?php
$data = array();

$conn = mysqli_connect("localhost", "root", "root") or die('Error connecting to MySQLserver.');
mysqli_select_db($conn, "Database") or die("Failed to connect to database");
$sql = "SELECT * FROM Servers";
$result = $conn->query($sql);
$servers = array();

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        $department = $row['department'];
        $serverMac = $row['serverMac'];
        $serverWindows = $row['serverWindows'];
        $serverLinux = $row['serverLinux'];
        $servers[] = getData($department, $serverMac, $serverWindows, $serverLinux);
    }

    printData($servers);

} else {
    echo "Unable to connection to server.  Please check your settings.";
}

function getData($serverMac, $serverWindows, $serverLinux) {

    //Gather Data About Server Mac
    //do something with the variable $serverMac

    //Gather Data About Server Windows
    //do something with the variable $serverWindows

    //Gather Data About Server Linux
    //do something with the variable $serverLinux

    //Put The Gathered Data In An Array
    $data = array(
        'department' => $department, 
        'macOS' => $macOS, 
        'macRAM' => $macRAM
        'windowsOS' => $windowsOS,
        'windowsRAM' => $windowsRAM,
        'linuxOS' => $linuxOS,
        'linuxRAM' => $linuxRAM);

    return $data;
}

function printData($data) {
    echo "<pre>";
    echo json_encode($data, JSON_PRETTY_PRINT);
    echo "</pre>";
}
?>