使用循环从PHP中的数据库中获取数据

Question

我想在数据库的视图中显示问题及其各自的答案：

我得到了名为Feedback的数据库表，格式如下：

这是我的表格名称：反馈

id | employee_id | question_id |   answer            |
______________________________________________________

1  |   100       |   1         | That was awesome. 
2  |   100       |   2         | That was excellent.  
3  |   100       |   3         | That was good.  
4  |   101       |   1         | That was better.  
5  |   101       |   2         | That was interesting.  
6  |   101       |   3         | That was fine.

还有另一个以问题命名的表格：

id |      Question        |
_______________________________________________

1  | How was your day? 
2  | How was the task?
3  | How was the Project?

这是我的模型代码：

function get_answers_supervisee () {
    $userid = $this->session->userdata('userid');
    $result = array ();
    $sql = "select answer from Feedback where employee_id = '$userid'";
    $query = $this->db->query ( $sql );
    foreach ( $query->result_array () as $row ) {
        array_push ( $result, $row );
    }
    return $result; 
}

下面是我的表单（客户端视图）：

<table class="table">       
     <?php foreach($form_data_supervisee as $question) {?>
     <tr>      
         <td>
         <?php echo $question['ID'].". ".$question['DESCRIPTION']?>
         </td>
    </tr>   
         <?php foreach($form_answers_supervisee as $answer) {?>                 
    <tr>   
          <td>
          <textarea rows="5" name="<?php echo $answer['ANSWER']?></textarea>
          </td> 
    </tr>   
    <?php } ?>  
    <?php }?> 
  </table>

这是我的控制器的一部分：

 $data['form_answers_supervisee'] = $this->appraisal_model->get_answers_supervisee();
     $data['form_answers_supervisor'] = $this->appraisal_model->get_answers_supervisor();

     $this->load->view('main_form',$data);

现在，对于具有 employee_id: 100

的员工，我得到以下输出

1. How was your day?
   That was awesome. 
   That was excellent.
   That was good.

2. How was the task?
   That was awesome. 
   That was excellent.
   That was good.

3. How was the Project?
   That was awesome. 
   That was excellent.
   That was good.

所需的输出应该是：

1. How was your day?
   That was awesome. 

2. How was the task?
   That was excellent.

3. How was the Project?
   That was good.

我需要在这里进行什么更正？我做错了什么？

非常感谢您的建议。

Answer 1

试试下面的

你的模型

function get_answers_supervisee () 
{
    $userid = $this->session->userdata('userid');

    $query = $this->db
        ->select('f.*, q.id AS question_id, q.Question')
        ->from('Feedback f')
        ->join('Questions q', 'f.question_id = q.id', 'left')
        ->where('employee_id', $userid)
        ->get();

    return $query->result();
}

控制器应该保持不变。

你的看法

<table class="table">       
     <?php 
     foreach($form_data_supervisee as $question) {
     ?>
     <tr>      
         <td>
         <p><?php echo $question->question_id.". ".$question->Question; ?></p>
         <p>Answer: <?php echo $question->answer; ?></p>
         </td>
    </tr>   
    <?php 
    }
    ?> 
</table>

补充说明：

您的查询对 sql 注入完全开放 - 您 真的应该为这些目的使用内置的 QueryBuilder 你自己好。

看这里 https://www.codeigniter.com/userguide3/database/configuration.html#query-builder 并激活查询生成器（如果您还没有）。

Answer 2

希望对您有所帮助：

你必须添加一个基于questions 表的join 查询和feedback 表，如下所示：

function get_answers_supervisee () 
{
    $employee_id = $this->session->userdata('userid');
    $this->db->select('q.id , q.question,f.answer ,f.employee_id');
    $this->db->from('questions q');
    $this->db->join('feedback f','f.question_id = q.id');
    $this->db->where('f.employee_id', $employee_id);
    $result = $this->db->get()->result();
    return $result;
    //print_r($result);
}

输出看起来像：

id  question                 answer           employee_id
1   How was your day?     That was awesome.     100
2   How was the task?     That was excellent.   100
3   How was the Project?  That was good.        100

您的view 访问表列如下：

<table class="table">       
     <?php foreach($form_data_supervisee as $item) {?>
     <tr>      
         <td>
         <?php echo $item->id;?>
         </td>
         <td>
         <?php echo $item->quesion;?>
         </td>
         <td>
         <?php echo $item->answer;?>
         </td>
      </tr>  

    <?php }?> 
</table>   

Answer 3

只需在视图中添加 if 语句即可根据问题输出答案。

 <table class="table">       
     <?php foreach($form_data_supervisee as $question) {?>
     <tr>      
         <td>
         <?php echo $question['ID'].". ".$question['DESCRIPTION']?>
         </td>
    </tr>   
         <?php foreach($form_answers_supervisee as $answer) {?>                 
    <tr>   
          <!-- check "id" in  "questions" table matches the "question_id" in "feedback" table --> 
          <?php if($question['ID'] == $answer['question_id']){ ?>
              <td>
                    <textarea rows="5" name="<?php echo $answer['ANSWER']?></textarea>
              </td>
          <?php } ?> 
    </tr>   
    <?php } ?>  
    <?php }?> 
  </table>

Answer 4

您好，您的查询必须基于 question_id

    <?php 

    function get_answers_supervisee ($question_id) {
        $userid = $this->session->userdata('userid');
        $result = array ();
        $sql = "select answer from Feedback where employee_id = '$userid' AND question_id = '$question_id' LIMIT 1";
        $query = $this->db->query ( $sql );
        foreach ( $query->result_array () as $row ) {
            array_push ( $result, $row );
        }
        return $result; 
    }

    ?>