【发布时间】:2020-03-10 02:28:19
【问题描述】:
public function parse()
{
$db4 = $this->load->database('db4', TRUE);
$query = $db4->query(' INSERT INTO test (nik, nama, status, bulan, tahun, hk, hb, lembur, gp, obat, transport, tunjangan, bpjs) SELECT (`karyawan`.`no_nik`, `karyawan`.`nama`, `karyawan`.`kd_status`, `absensi`.`bulan`, `absensi`.`tahun`, `absensi`.`hk`, `absensi`.`hari_besar`, `absensi`.`lembur`, `karyawan`.`gapok`, `karyawan`.`obat`, `karyawan`.`transport`, `karyawan`.`tunjangan`, `karyawan`.`bpjs`) FROM karyawan LEFT JOIN absensi ON `karyawan`.`no_nik` = `absensi`.`nik` ');
}
【问题讨论】:
标签: mysql codeigniter