【发布时间】:2014-04-06 20:12:43
【问题描述】:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /rideanddrive/_classes/__base.php on line 45
我的代码:
public static function SelectSpecific($obj, $data_base, $cond)
{
self::$query = "select $obj from " . self::$baseprefix . "$data_base where $cond";
$out = self::Execute();
$array = mysql_fetch_array($out); // THIS LINE IS WARNING LINE
return $array[$obj];
}
如果需要,执行函数:
private static function Execute()
{
$out = mysql_query(self::$query);
return $out;
}
代码运行良好。我在本地主机上没有收到警告(运行 WAMP,可能已将其关闭?),它也适用于实时服务器,但是我收到上述警告,我该如何纠正它以使警告消失?
【问题讨论】:
标签: php mysql database mysqli fetch