如何在python中的一条水平线上打印3个骰子答案

【问题标题】：How to print 3 dice on one horizontal line in python如何在python中的一条水平线上打印3个骰子
【发布时间】：2021-02-18 19:22:47
【问题描述】：

我在 python 中有这段代码，代码通过输入 (r) 而不是水平方向打印每个骰子。有谁知道如何编辑此代码以水平打印 3 个骰子？

Screenshot

import random

x = "r"

while x == "r":
  no = random.randint(1,6)
  if no == 1: 
    print("[-----]") 
    print("[     ]") 
    print("[  0  ]") 
    print("[     ]") 
    print("[-----]")
  if no == 2: 
    print("[-----]") 
    print("[ 0   ]") 
    print("[     ]") 
    print("[   0 ]") 
    print("[-----]") 
  if no == 3: 
    print("[-----]") 
    print("[     ]") 
    print("[0 0 0]") 
    print("[     ]") 
    print("[-----]")
  if no == 4: 
    print("[-----]") 
    print("[0   0]") 
    print("[     ]") 
    print("[0   0]") 
    print("[-----]") 
  if no == 5: 
    print("[-----]") 
    print("[0   0]") 
    print("[  0  ]") 
    print("[0   0]") 
    print("[-----]") 
  if no == 6: 
    print("[-----]") 
    print("[0 0 0]") 
    print("[     ]") 
    print("[0 0 0]") 
    print("[-----]")  

  x=input("press r to roll again or e to exit:") 

  print("\n")

【问题讨论】：

标签： python printing output line dice

【解决方案1】：

您可以使用列表来存储骰子字符串。附加到每个掷骰子的字符串。

这将为每一轮打印连续的骰子：

import random

def drawdice(nums):
    rows = []  # all dice
    for no in nums:
      if no == 1: 
        rows.append(
        "[-----]" 
        "[     ]" 
        "[  0  ]" 
        "[     ]" 
        "[-----]")
      if no == 2: 
        rows.append(
        "[-----]" 
        "[ 0   ]" 
        "[     ]" 
        "[   0 ]" 
        "[-----]") 
      if no == 3: 
        rows.append(
        "[-----]" 
        "[     ]" 
        "[0 0 0]" 
        "[     ]" 
        "[-----]")
      if no == 4: 
        rows.append(
        "[-----]" 
        "[0   0]" 
        "[     ]" 
        "[0   0]" 
        "[-----]") 
      if no == 5: 
        rows.append(
        "[-----]" 
        "[0   0]" 
        "[  0  ]" 
        "[0   0]" 
        "[-----]") 
      if no == 6: 
        rows.append(
        "[-----]" 
        "[0 0 0]" 
        "[     ]" 
        "[0 0 0]" 
        "[-----]")  
      
    for rx in range(5):  # each row in dice
       for ry in rows:
          print(ry[rx*7:(rx+1)*7], end=' ')  # each dice
       print() # next row

print()
x = 'r'
while x != 'e':
  rolls = [random.randint(1,6) for n in range(3)]  # 3 dice
  drawdice(rolls)
  print("")  
  x=input("press enter to roll again or e to exit: ") 
  print("")

输出

[-----] [-----] [-----]
[     ] [0   0] [     ]
[  0  ] [  0  ] [0 0 0]
[     ] [0   0] [     ]
[-----] [-----] [-----]

press enter to roll again or e to exit:

[-----] [-----] [-----]
[     ] [ 0   ] [     ]
[0 0 0] [     ] [0 0 0]
[     ] [   0 ] [     ]
[-----] [-----] [-----]

press enter to roll again or e to exit:

[-----] [-----] [-----]
[0 0 0] [0   0] [0   0]
[     ] [     ] [     ]
[0 0 0] [0   0] [0   0]
[-----] [-----] [-----]

为了完整起见，您还可以将骰子字符串打包在一个列表中以供显示

def drawdice(nums):

    dice = [
    ["[-----]","[-----]","[-----]","[-----]","[-----]","[-----]"],
    ["[     ]","[ 0   ]","[     ]","[0   0]","[0   0]","[0 0 0]"],
    ["[  0  ]","[     ]","[0 0 0]","[     ]","[  0  ]","[     ]"],
    ["[     ]","[   0 ]","[     ]","[0   0]","[0   0]","[0 0 0]"],
    ["[-----]","[-----]","[-----]","[-----]","[-----]","[-----]"]
    ]
    
    for rx in dice:  # each row in dice
       for no in nums:
          print(rx[no-1], end=' ')
       print()

输出是一样的

【讨论】：

每掷一次，骰子数就会增加。答案更新为完整输出。
感谢您的回复...现在输出从 1 开始到 ~ dice 那么我如何才能在每行仅获得 3 个 dice？
非常感谢这就是我想要的......你是天才
嗨，迈克，你能帮我编写 Python 脚本吗？我有代码，但如果可能的话，我想以不同的方式编写它。