从星期几和时间计算出 PHP 中的未来日期答案

【问题标题】：Working out future dates in PHP from days of week and times从星期几和时间计算出 PHP 中的未来日期
【发布时间】：2015-02-09 10:09:39
【问题描述】：

我有以下数组，其中包含星期几 (0-6) 和以小时、分钟和秒为单位的时间：

$times = array(     array("1","10:04:00"),
                    array("1","14:20:00"),
                    array("1","20:30:00"),
                    array("1","22:22:00"),
                    array("2","10:14:00"),
                    array("2","14:36:00"),
                    array("2","20:12:00"),
                    array("2","22:42:00"),
                    array("3","12:04:00"),
                    array("3","15:20:00"),
                    array("3","21:30:00"),
                    array("4","23:22:00"),
                    array("4","09:04:00"),
                    array("4","12:20:00"),
                    array("4","19:30:00"),
                    array("4","22:32:00"),
                    array("5","13:04:00"),
                    array("5","16:20:00"),
                    array("5","20:10:00"),
                    array("5","22:02:00")
                    );

如何循环上述内容并确定活动的下一个日期？例如，如果今天是星期二，则上述数组中的前几个日期将是：

下周一 10:04:00 下周一 14:20:00 下周一 20:30:00 下周一 22:22:00 今天 10:14:00 今天 14:36:00 等等……

一旦循环到达上述数组的末尾，它将循环回到开头，因此需要计算出未来的日期。日期和时间需要转换为 unix 日期时间。

这是目前为止的脚本：

$row = 1;
if (($handle = fopen("evergreen.csv", "r")) !== FALSE) {
        $loopy = 0;
        $thisWeek = date("W");
  while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
        if(!isset($times[$loopy])) {$loopy = 0;}
        $dayoftheweek = $times[$loopy][0];
        $thetime      = $times[$loopy][1];
        echo "Day: $dayoftheweek - The time: $thetime<br />";
        // How can I work out the next date and time to post from this?
        $loopy++;
  }
  fclose($handle);
}

我不知道如何实现上述目标。任何帮助将不胜感激。

谢谢！

【问题讨论】：

只需编写一个函数并在数组中循环，这没什么大不了的。
是的，循环很简单。它将星期几和时间转换为 unix 日期，无论是在过去还是将来，它都可以工作。我会在问题中更清楚地说明这一点。

标签： php date datetime

【解决方案1】：

要操作日期，您可以使用strtotime()。直接来自php.net 网站的示例：

<?php
echo strtotime("now"), "\n";
echo strtotime("10 September 2000"), "\n";
echo strtotime("+1 day"), "\n";
echo strtotime("+1 week"), "\n";
echo strtotime("+1 week 2 days 4 hours 2 seconds"), "\n";
echo strtotime("next Thursday"), "\n";
echo strtotime("last Monday"), "\n";

在您的情况下，您可以将时间放在第二个参数中：

strtotime("+1 day", $timefromloop);

【讨论】：

【解决方案2】：

只需“询问”strtotime 或 DateTime

<?php
$weekdays = array(
    '1'=>'monday',
    '2'=>'tuesday',
    '3'=>'wednesday',
    '4'=>'thursday',
    '5'=>'friday'
);
$currentDay = getdate()['wday']; // for php < 5.4 there is no function array de-reference

$times = array(
    array("1","10:04:00"),
    array("1","14:20:00"),
    array("1","20:30:00"),
    array("1","22:22:00"),
    array("2","10:14:00"),
    array("2","14:36:00"),
    array("2","20:12:00"),
    array("2","22:42:00"),
    array("3","12:04:00"),
    array("3","15:20:00"),
    array("3","21:30:00"),
    array("4","23:22:00"),
    array("4","09:04:00"),
    array("4","12:20:00"),
    array("4","19:30:00"),
    array("4","22:32:00"),
    array("5","13:04:00"),
    array("5","16:20:00"),
    array("5","20:10:00"),
    array("5","22:02:00")
);

$times = array_map(function($e) use ($weekdays, $currentDay) {
        $q = $weekdays[ $e[0] ]; // get the name of the weekday for strtotime
        $q.= ' '.$e[1]; // append the time of the event

        if ( $e[0]==$currentDay ) {
            return strtotime($q);
        }
        else {
            // for any other day than today "ask" strtotime for the next/coming day with that name
            return strtotime('next '.$q);
        }
    },
    $times
);


foreach($times as $ts) {
    echo date('Y-m-d H:i:s', $ts), "\r\n";
}

打印（今天）

2015-02-09 10:04:00
2015-02-09 14:20:00
2015-02-09 20:30:00
2015-02-09 22:22:00
2015-02-10 10:14:00
2015-02-10 14:36:00
2015-02-10 20:12:00
2015-02-10 22:42:00
2015-02-11 12:04:00
2015-02-11 15:20:00
2015-02-11 21:30:00
2015-02-12 23:22:00
2015-02-12 09:04:00
2015-02-12 12:20:00
2015-02-12 19:30:00
2015-02-12 22:32:00
2015-02-13 13:04:00
2015-02-13 16:20:00
2015-02-13 20:10:00
2015-02-13 22:02:00

【讨论】：