在 PHP 中简化数组

Question

我有以下需要在 PHP 中定义的数组，我已经以非常基本的方式完成了：

$ch1 = array("A-MTP-1-1","A-MTP-1-2","A-MTP-1-3","A-MTP-1-4"); 
$ch2 = array("A-MTP-1-5","A-MTP-1-6","A-MTP-1-7","A-MTP-1-8"); 
$ch3 = array("A-MTP-1-9","A-MTP-1-10","A-MTP-1-11","A-MTP-1-12");

$ch4 = array("A-MTP-2-1","A-MTP-2-2","A-MTP-2-3","A-MTP-2-4"); 
$ch5 = array("A-MTP-2-5","A-MTP-2-6","A-MTP-2-7","A-MTP-2-8"); 
$ch6 = array("A-MTP-2-9","A-MTP-2-10","A-MTP-2-11","A-MTP-2-12");

$ch7 = array("A-MTP-3-1","A-MTP-3-2","A-MTP-3-3","A-MTP-3-4"); 
$ch8 = array("A-MTP-3-5","A-MTP-3-6","A-MTP-3-7","A-MTP-3-8"); 
$ch9 = array("A-MTP-3-9","A-MTP-3-10","A-MTP-3-11","A-MTP-3-12");

但我在想必须有一种简单的方法来写这个而不是写出每一个但不确定从哪里开始，有人能指出我正确的方向来简化这个 PHP，因为我也会重复它适用于上述情况，但每个都用 B 而不是 A。

Answer 1

使用 range() 、 array_chunk 和 extract 来完成这项工作

<?php

for ($i = 1; $i <= 3; $i++) {           # Pass 3 as you need three sets
    foreach (range(1, 12) as $val) {    # 1,12 again as per your requirements
        $arr[] = "A-MTP-$i-" . $val;

    }
}
foreach (array_chunk($arr, 4) as $k => $arr1) {    # Loop the array chunks and set a key
    $finarray["ch" . ($k + 1)] = $arr1;
}
extract($finarray);   # Use the extract on that array so you can access each array separately
print_r($ch9);        # For printing the $ch9 as you requested.

Demo

OUTPUT :（仅$ch9 部分的插图）

Array
(
    [0] => A-MTP-3-9
    [1] => A-MTP-3-10
    [2] => A-MTP-3-11
    [3] => A-MTP-3-12
)

完成后，您可以使用array_chunk 将数组拆分为长度为4。