【发布时间】:2015-10-14 02:59:31
【问题描述】:
首先,请注意我并没有将其用作真实世界的登录,这纯粹是为了练习。我正在使用 PHP/MySQLi,并且我试图实现准备好的语句,但我没有正确执行。这是我的工作代码,只有 mysqli_escape_string:
$host="localhost";
$username="login";
$password="password";
$db_name="database";
$link=mysqli_connect("$host", "$username", "$password", "$db_name")or die("cannot connect to server");
$tbl_name=temp_members;
// Random confirmation code to be sent in email
$confirm_code=md5(uniqid(rand()));
//from signup.php
$name=$_POST['name'];
$email=$_POST['email'];
$pwd=$_POST['password'];
$name = mysqli_real_escape_string($link, $name);
$email = mysqli_real_escape_string($link, $email);
$pwd = mysqli_real_escape_string($link, $pwd);
$pwd = password_hash($pwd, PASSWORD_DEFAULT);
// Insert data into temp_members
$sql="INSERT INTO $tbl_name(confirm_code, name, email, password)VALUES('$confirm_code', '$name', '$email', '$pwd')";
$result=mysqli_query($link, $sql);
if($result){
//email
$to=$email;
$subject="(no reply)";
$header="from: Ben Pappas <mrbenpappas@gmail.com>";
// message
$message="Hello ".$name.", Thanks for signing up! \r\n";
$message.="Click on this link to activate your account: \r\n";
$message.="http://www.monger.us/verify/confirmation.php? passkey=$confirm_code";
// send email
$sentmail = mail($to,$subject,$message,$header);
}
这是我对 PDO/prepared statements 的(糟糕的)尝试:
$host="localhost";
$username="login";
$password="password";
$db_name="database";
$link = new PDO("mysql:host=$host;dbname=$db_name",$username,$password) or die("cannot connect to server");
$tbl_name=temp_members;
// Random confirmation code to be sent in email
$confirm_code=md5(uniqid(rand()));
//from signup.php
$name=$_POST['name'];
$email=$_POST['email'];
$pwd=$_POST['password'];
$name = mysqli_real_escape_string($link, $name);
$email = mysqli_real_escape_string($link, $email);
$pwd = mysqli_real_escape_string($link, $pwd);
$pwd = password_hash($pwd, PASSWORD_DEFAULT);
// Insert data into temp_members
$statement = $link->prepare("INSERT INTO $tbl_name(confirm_code, name, email, password)VALUES('$confirm_code', '$name', '$email', '$pwd')";
$statement->execute(array(
$confirm_code => 'confirm_code',
$email => 'email',
$name => 'name'
));
$result = ($link, $statement);
if($result){
//email
$to=$email;
$subject="(no reply)";
$header="from: Ben Pappas <mrbenpappas@gmail.com>";
// message
$message="Hello ".$name.", Thanks for signing up! \r\n";
$message.="Click on this link to activate your account: \r\n";
$message.="http://www.monger.us/verify/confirmation.php? passkey=$confirm_code";
// send email
$sentmail = mail($to,$subject,$message,$header);
}
我在调用语句变量的那一行出现错误,并显示一条消息意外“;”
请原谅任何明显的错误我是学徒
【问题讨论】:
-
我认为这行右括号缺少 $statement = $link->prepare("INSERT INTO $tbl_name(confirm_code, name, email, password)VALUES('$confirm_code', '$name ', '$email', '$pwd')";
标签: php mysql pdo prepared-statement