我已经构建了一个 grep 命令，用于在文件目录中递归搜索其中的模式。问题是 grep 只返回模式所在的文件名，而不是模式的完全匹配。如何返回实际结果？
例子：
文件somefile.bin 包含somestring0987654321�123�45� 与一百万个其他文件的目录
命令：
$ grep -EsniR -A 1 -B 1 '([a-zA-Z0-9]+)\x00([0-9]+)\x00([0-9]+)\x00' *
当前结果：
Binary file somefile.bin matches
想要的结果（或接近）：
Binary file somefile.bin matches
<line above match>
somestring0987654321�123�45�
<line below match>
【问题讨论】：
您可以尝试-a 选项：
File and Directory Selection
-a, --text
Process a binary file as if it were text; this is equivalent to
the --binary-files=text option.
--binary-files=TYPE
If the first few bytes of a file indicate that the file contains
binary data, assume that the file is of type TYPE. By default,
TYPE is binary, and grep normally outputs either a one-line
message saying that a binary file matches, or no message if
there is no match. If TYPE is without-match, grep assumes that
a binary file does not match; this is equivalent to the -I
option. If TYPE is text, grep processes a binary file as if it
were text; this is equivalent to the -a option. Warning: grep
--binary-files=text might output binary garbage, which can have
nasty side effects if the output is a terminal and if the
terminal driver interprets some of it as commands.
但问题是在二进制文件中没有行，所以我不确定您希望输出是什么样的。您会看到随机垃圾，可能是整个文件，可能会打印一些与您的终端混淆的特殊字符。
如果您想将输出限制为匹配本身，请考虑使用-o 选项：
-o, --only-matching
Print only the matched (non-empty) parts of a matching line,
with each such part on a separate output line.
上下文控制仅限于在匹配之前或之后添加一定数量的行，这在这里可能无法正常工作。因此，如果您想要特定字节数的上下文，则必须更改模式本身。
【讨论】：
-o 选项。
试试……
grep -rnw "<regex>" <folder>
容易得多。更多示例在这里 --> https://computingbro.com/2020/05/10/word-search-in-linux-unix-filesystem/
【讨论】：