【发布时间】:2012-04-09 19:41:34
【问题描述】:
我有3张表如下:
products:[product_id,product_name]
stock:[product_id,date,qty_received]
sales:[product_id,date,qty_sold]
我试图通过减去 qty_received - qty_sold 来显示所有产品的余额。 我的查询是:
SELECT DISTINCT p.product_id, p.product_name,
IFNULL(sum(qty_received),0)-IFNULL(sum(qty_sold),0) as balance FROM products p
LEFT JOIN stock st ON (p.product_id=st.product_id)
LEFT JOIN sales sa ON (p.product_id=sa.product_id)
GROUP BY p.product_id
通过上述查询,我没有得到正确的余额。 你能帮忙吗?
附加信息: 以下是我的表格的简化结构 产品表:
CREATE TABLE IF NOT EXISTS `products` (
`product_id` varchar(15) NOT NULL,
`product_name` varchar(20) NOT NULL,
UNIQUE KEY `product_id` (`product_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
-- 转储表products的数据
INSERT INTO `products` (`product_id`, `product_name`) VALUES
('111', 'Product One'),
('222', 'Product Two'),
('333', 'Product Three'),
('444', 'Product Four');
库存表:
CREATE TABLE IF NOT EXISTS `stock` (
`stock_id` int(11) NOT NULL AUTO_INCREMENT,
`product_id` int(11) NOT NULL,
`qty_received` int(11) NOT NULL,
PRIMARY KEY (`stock_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=112 ;
-- 转储表stock的数据
INSERT INTO `stock` (`stock_id`, `product_id`, `qty_received`) VALUES
(1, 111, 5),
(2, 222, 10),
(3, 333, 4),
(4, 444, 6),
(5, 111, 2),
(6, 222, 7),
(7, 111, 3),
(8, 111, 3);
销售表
CREATE TABLE IF NOT EXISTS `sales` (
`sales_id` int(11) NOT NULL AUTO_INCREMENT,
`product_id` int(11) NOT NULL,
`qty_sold` int(11) NOT NULL,
PRIMARY KEY (`sales_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=7 ;
-- 转储表sales的数据
INSERT INTO `sales` (`sales_id`, `product_id`, `qty_sold`) VALUES
(1, 111, -1),
(2, 222, -3),
(3, 333, -2),
(4, 111, -3),
(5, 222, -1),
(6, 222, -4);
我得到的结果是:
+------------+--------------+---------+
| product_id | product_name | balance |
+------------+--------------+---------+
| 111 | Product One | 10 |
| 222 | Product Two | 35 |
| 333 | Product Three| 2 |
| 444 | Product Four | 6 |
+------------+--------------+---------+
我期望的正确平衡是
+------------+--------------+---------+
| product_id | product_name | balance |
+------------+--------------+---------+
| 111 | Product One | 9 |
| 222 | Product Two | 9 |
| 333 | Product Three| 2 |
| 444 | Product Four | 6 |
+------------+--------------+---------+
终于得到了这个解决方案的工作 sql,但不确定这是否是最好的方法。我非常关心性能,因为这些表有大量记录。
SELECT p.product_id,p.product_name,
IFNULL(sum(st.qty_received),0)+IFNULL(sold,0) as balance FROM products p
LEFT JOIN stock st ON (p.product_id=st.product_id)
LEFT JOIN (SELECT sa.product_id,sum(sa.qty_sold) as sold FROM sales sa
GROUP BY sa.product_id) as t1 ON (t1.product_id=p.product_id)
GROUP BY product_id
任何人都可以建议更好的 sql(或架构更改)以获得更好的速度/性能来获得库存平衡?
【问题讨论】:
-
sales.qty_sold是否有可能被存储为负数? -
是的,sales.qty_sold 存储为负数,希望它可以让事情变得更容易。
-
那你就有答案了。您需要 添加
sum(qty_sold)而不是 减去 它以获得正确的结果。...IFNULL(sum(qty_received),0)+IFNULL(sum(qty_sold),0) as balance... -
@asiph 您当前查询的输入、正确输出和错误输出示例将帮助人们回答。简单地告诉我们“它仍然不起作用”让我们在黑暗中拍摄,可以这么说。