为什么我的 LEFT JOIN 没有返回预期的结果集？

Question

我正在使用带有 ON 子句的 LEFT JOIN 执行查询，但它似乎没有正确运行。

相关架构：

cdrs

id [primary key - auto incrementing]
aparty [VARCHAR(50)]
bparty [VARCHAR(50)]

费率

id [primary key - auto incrementing]
apartypattern [VARCHAR(50)]
bpartypattern [VARCHAR(50)]

可能有多个模式匹配一​​个 cdr。如果从左到右阅读，模式的所有字符从相关 cdr 字段的开头按顺序出现，则认为模式匹配。 当存在多个匹配时，描述匹配条件的逻辑可以表示为：

ORDER BY LENGTH(bpartypattern), LENGTH(apartypattern) LIMIT 1

我正在尝试通过以下查询来实现这一点：

SELECT c.id, r_a.id
FROM cdrs c
LEFT JOIN (
  SELECT id, LENGTH(apartypattern) AS maxlen, apartypattern
  FROM rates
) r_a ON c.aparty LIKE CONCAT(r_a.apartypattern,'%')
LEFT JOIN (
  SELECT id, LENGTH(bpartypattern) AS maxlen, bpartypattern
  FROM rates
) r_b ON c.bparty LIKE CONCAT(r_b.bpartypattern,'%')
WHERE r_a.id = r_b.id
GROUP BY c.id
ORDER BY r_b.maxlen DESC, r_a.maxlen DESC

但是我得到的结果与我将 WHERE 子句替换为：

WHERE r_a.id = 1 AND r_b.id = 1

在手动检查数据集后，有明显应该匹配但没有匹配的行。

作为进一步的故障排除步骤，我尝试按如下方式简化查询，但仍会得到结果，就像应用了替代 WHERE 子句一样：

SELECT c.id, r_a.id
FROM cdrs c
LEFT JOIN (
  SELECT id, LENGTH(aparty) AS len, apartypattern
  FROM rates
) r ON c.aparty LIKE CONCAT(r_a.apartypattern,'%')

Answer 1

SELECT 
c.id, 
r.id
LENGTH(r.apartypattern) as `r_l`,
LENGTH(r.bpartypattern) as `r_b`
FROM cdrs c
LEFT JOIN rates r ON c.aparty LIKE CONCAT(r.apartypattern,'%') AND
                     c.bparty LIKE CONCAT(r.bpartypattern,'%')
ORDER BY `r_l` DESC, `r_b` DESC