【发布时间】:2023-04-08 00:06:01
【问题描述】:
我正在创建一个应用程序来管理 game 和 team 数据。这是 mySQL 数据库结构:
CREATE TABLE team (
id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(50) NOT NULL,
PRIMARY KEY (id)
);
CREATE TABLE game (
id INT NOT NULL AUTO_INCREMENT,
id_team_A INT NOT NULL,
id_team_B INT NOT NULL,
PRIMARY KEY (id)
);
-- TEST VALUES: --
INSERT INTO team VALUES
(1, "Barcelona"),
(2, "Milan"),
(3, "Real Madrid"),
(4, "Inter");
INSERT INTO game VALUES
(1, 1, 3),
(2, 2, 4);
如您所见,每个 match 都有 2 个不同的 team 关联。
我正在尝试(没有成功)进入单个查询匹配 id、团队 A 名称、团队 B 名称。
首先我尝试了这样的查询:
SELECT game.id, team.name, team.name
FROM team INNER JOIN game
ON game.id_team_A = team.id;
但我的查询不关心 match.id_team_B 并且重复的 match.name 字段不会解决问题。
然后我开始使用嵌套在一起的选择查询:
SELECT @g_id := game.id as id,
(SELECT team.name FROM team INNER JOIN game ON game.id_team_A = team.id WHERE game.id = @g_id) AS team_A,
(SELECT team.name FROM team INNER JOIN game ON game.id_team_B = team.id WHERE game.id = @g_id) AS team_B
FROM game;
最后我得到了我想要的:
+-----+---------------+---------------+
| id | team_A | team_B |
+-----+---------------+---------------+
| 1 | Barcelona | Real Madrid |
+-----+---------------+---------------+
| 2 | Milan | Inter |
+-----+---------------+---------------+
是否有更简单/更快/更酷的查询来获得相同的结果?
注意:SQL Fiddle
【问题讨论】:
标签: mysql inner-join