【发布时间】：2015-08-09 18:09:24
【问题描述】：
我试图解决这个问题好几天，但没有成功。我希望你的专业知识：
我想要实现的分组，同样位于：http://imgur.com/q8qoAVQ
sqlfiddle 上提供的示例：http://sqlfiddle.com/#!9/e42e6/2
DDL 和示例数据：
CREATE TABLE tx_management_domain_model_events (
`uid` int(11) NOT NULL,
`title` varchar(255),
PRIMARY KEY(uid)
);
CREATE TABLE tx_management_domain_model_programm (
`uid` int(11) NOT NULL,
`jobtype` int(11) unsigned DEFAULT '0' NOT NULL,
`reservation` int(11) DEFAULT '0' NOT NULL,
`eventdate` date NULL,
`event` int(11) DEFAULT '0' NOT NULL,
PRIMARY KEY(uid)
);
CREATE TABLE tx_management_domain_model_reservations (
`uid` int(11) NOT NULL,
`event` int(11) default '0',
`feuser` int(11) DEFAULT '0',
`status` int(11) DEFAULT '0' NOT NULL,
`ressource` int(11) DEFAULT '0',
PRIMARY KEY(uid)
);
CREATE TABLE tx_management_domain_model_appointments (
`uid` int(11) NOT NULL,
`begin` int(11) DEFAULT '0' NOT NULL,
`end` int(11) DEFAULT '0' NOT NULL,
`event` int(11) unsigned DEFAULT '0' NOT NULL,
PRIMARY KEY(uid)
);
CREATE TABLE tx_management_domain_model_additionalcosts (
`uid` int(11) NOT NULL,
`additionalcosttype` int(11) unsigned DEFAULT '0' NOT NULL,
`event` int(11) DEFAULT '0' NOT NULL,
`feuser` int(11) DEFAULT '0' NOT NULL,
`reservation` int(11) DEFAULT '0' NOT NULL,
PRIMARY KEY (uid)
);
CREATE TABLE tx_management_domain_model_referents (
`uid` int(11) NOT NULL,
`specialsallary` text NULL,
`feuser` int(11) unsigned DEFAULT '0' NOT NULL,
`event` int(11) unsigned DEFAULT '0' NOT NULL,
PRIMARY KEY(uid)
);
CREATE TABLE fe_users (
`uid` int(11) NOT NULL,
`fullname` varchar(255),
PRIMARY KEY(uid)
);
# ---------------------- Fill with data --------------------
INSERT INTO tx_management_domain_model_events
(`uid`, `title`)
VALUES
(1660, 'Event-1'),
(1632, 'Event-2');
INSERT INTO tx_management_domain_model_programm
(`uid`, `jobtype`, `reservation`, `event`, `eventdate`)
VALUES
(1149, 2, 11259, 1660, '2015-05-04'),
(1154, 0, 11278, 1660, '2015-05-04'),
(1534, 0, 11783, 1660, '2015-07-11');
INSERT INTO tx_management_domain_model_reservations
(`uid`, `event`, `feuser`, `status`, `ressource`)
VALUES
(11259, 1660, 116740, 1105, 19901),
(11278, 1660, 116740, 1105, 19901),
(11280, 1660, 117354, 1101, 19902),
(11783, 1660, 116740, 1101, 19901),
(11784, 1660, 116740, 1101, 100001);
INSERT INTO tx_management_domain_model_appointments
(`uid`, `begin`, `end`, `event`)
VALUES
(1104, 1430690400, 1432936800, 1660),
(1123, 1436565600, 1436652000, 1660),
(1127, 1436306400, 1436911200, 1632);
INSERT INTO tx_management_domain_model_additionalcosts
(`uid`, `additionalcosttype`, `event`, `feuser`, `reservation`)
VALUES
(1, 0, 1660, 11740, 11784);
INSERT INTO tx_management_domain_model_referents
(`uid`, `specialsallary`, `feuser`, `event`)
VALUES
(1885, '', 116740, 1660),
(1935, '', 116740, 1632);
INSERT INTO fe_users
(`uid`, `fullname`)
VALUES
(116740, 'John Kohn');
SQL 查询：
select
group_concat(distinct tbl_events.uid) as Event,
date_format(from_unixtime(tbl_appointments.`begin`),get_format(DATE, 'EUR')) AS 'appointmentBegin',
date_format(from_unixtime(tbl_appointments.`end`),get_format(DATE, 'EUR')) AS 'appointmentEnd',
group_concat(distinct tbl_reservations.ressource) as Ressource,
group_concat(distinct tbl_programm.jobtype) as Jobtyp,
group_concat(tbl_reservations.uid) AS Reservations,
group_concat(distinct tbl_referents.specialsallary) AS Specialsallary
from
tx_management_domain_model_events tbl_events
inner join tx_management_domain_model_reservations as tbl_reservations on tbl_reservations.event = tbl_events.uid
inner join tx_management_domain_model_appointments as tbl_appointments on tbl_events.uid = tbl_appointments.event
left join tx_management_domain_model_programm as tbl_programm on tbl_reservations.uid = tbl_programm.reservation and tbl_programm.eventdate between from_unixtime(tbl_appointments.`begin`) and from_unixtime(tbl_appointments.`end`)
left join tx_management_domain_model_additionalcosts as tbl_additionalcosts on tbl_reservations.uid = tbl_additionalcosts.reservation
inner join fe_users on tbl_reservations.feuser = fe_users.uid
inner join tx_management_domain_model_referents as tbl_referents on tbl_reservations.feuser = tbl_referents.feuser
where tbl_reservations.feuser = 116740
and tbl_reservations.ressource in (19901,19902,100001,100002)
and tbl_referents.event = tbl_events.uid
and tbl_programm.event = tbl_events.uid
group by
tbl_events.uid,
CASE WHEN (tbl_reservations.ressource in (19901,19902,100001,100002) AND ((tbl_referents.specialsallary IS NULL) OR (tbl_referents.specialsallary LIKE ''))) THEN tbl_reservations.ressource ELSE tbl_referents.specialsallary END,
from_unixtime(tbl_appointments.`begin`),
from_unixtime(tbl_appointments.`end`),
tbl_programm.jobtype;
问题：没有显示 tx_management_domain_model_additionalcosts 中的记录。
预期：预订“11784”也应该在结果列“预订”中。
提示：如果我注释掉 tbl_programm 的每个 WHERE 条件，则会显示 tbl_additionalcosts 的记录。但为什么我必须删除这些条件？
有人知道我哪里出了问题吗？
【问题讨论】：
-
您应该在问题中包含示例数据和所需的结果。 Stack Overflow 问题不应依赖于其他网站才有意义。
-
这里应该包括什么？如您所见，数据太多
-
如果数据太多，那么您并没有将问题归结为核心。将您的示例最小化为简单的东西。我们希望问题对未来的访问者也有用，如果他们和您有同样的问题，他们需要快速理解。所以试着概括你的问题
-
抱歉，我无法处理您的命名政策
-
但是，请注意
CASE WHEN (r.ressource in (19901,19902,100001,100002)是多余的，因为 r.ressource 始终是这些代码之一......并且LEFT JOIN programm... WHERE programm...=INNER JOIN programm... WHERE programm