【发布时间】:2021-06-10 13:33:19
【问题描述】:
我使用 MySQL 在 Node.Js 上执行了以下查询:
SELECT COUNT(DISTINCT t.uid) AS usersCount, COUNT(*) AS workingDaysCount
FROM (
SELECT d.date, u.id AS uid,
CASE TIMESTAMPDIFF(day, SUBDATE(d.date, WEEKDAY(d.date)), d.date)
WHEN 0 THEN w.monday
WHEN 1 THEN w.tuesday
WHEN 2 THEN w.wednesday
WHEN 3 THEN w.thursday
WHEN 4 THEN w.friday
WHEN 5 THEN w.saturday
WHEN 6 THEN w.sunday
ELSE NULL
END AS working_day
FROM (
SELECT date_range.date
FROM (
SELECT CURDATE() - INTERVAL (sign.a * (a.a + (10 * b.a) + (100 * c.a) + (1000 * e.a) )) DAY AS date
FROM (SELECT -1 AS a UNION ALL SELECT 1) AS sign
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS e
ORDER BY date DESC
) date_range
WHERE date_range.Date BETWEEN DATE('2021-06-10') AND DATE('2021-06-10')) d, users u
LEFT OUTER JOIN working_days w ON w.id = (
SELECT id
FROM working_days
WHERE user_id = u.id AND week_start_date <= d.date
ORDER BY week_start_date DESC
LIMIT 1
)
WHERE u.id IN (4)
GROUP BY d.date, u.id
) t
WHERE t.working_day = 1;
在 Linux 服务器上它工作正常,所以我不知道问题出在哪里,但在 Windows 上我有以下错误:
#1054 - Unknown column 'd.date' in 'where clause'
我已经查看了代码并调试了几个小时,但我没有找到任何关于此的答案。请问有人有什么想法吗?
【问题讨论】:
-
也许我遗漏了一些东西,但我没有看到表别名
d的定义。 MySQL 会同意这一点,我应该注意。 -
@GordonLinoff 我想这应该像别名
WHERE date_range.Date BETWEEN DATE('2021-06-10') AND DATE('2021-06-10')) d, users u -
DISTINCT不是一个函数,它是一个集合量词!跳过那些多余的括号,直接写COUNT(DISTINCT t.uid)让代码更清晰。 -
LEFT OUTER JOIN的ON子句只能访问u和w列。当您混合使用显式JOIN和隐式的逗号分隔连接时,就会发生这种情况。到处切换到显式JOIN,问题就消失了! -
顺便说一句,您的 Windows MySQL 版本可能比 Linux 版本新,并且该行为已得到纠正。
标签: javascript mysql sql node.js