【发布时间】：2013-12-20 13:31:28
【问题描述】：
我无法显示 MySQL 数据库中的数据。我想从我的数据库中检索一些数据并将其显示到 textview，但它不起作用。
Java 代码：
public class Penjualan1 extends Activity {
// All xml labels
String pid;
TextView mejaTv;
TextView customerTv;
TextView keteranganTv;
// Progress Dialog
private ProgressDialog pDialog;
// Creating JSON Parser object
JSONParser jsonParser = new JSONParser();
// Profile JSON url
private static final String url_order_detials = "-my url-/get_penjualan_details.php";
// ALL JSON node names
private static final String TAG_PRODUCT = "product";
private static final String TAG_SUCCESS = "success";
private static final String TAG_GET = "get";
private static final String TAG_MEJA = "meja";
private static final String TAG_CUST = "customer";
private static final String TAG_KET = "keterangan";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.f_penjualan1);
mejaTv = (TextView) findViewById(R.id.meja);
customerTv = (TextView) findViewById(R.id.customer);
keteranganTv = (TextView) findViewById(R.id.keterangan);
// Loading Profile in Background Thread
new GetProductDetails().execute();
}
/**
* Background Async Task to Get complete product details
* */
class GetProductDetails extends AsyncTask<String, String, String> {
/**
* Before starting background thread Show Progress Dialog
* */
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(Penjualan1.this);
pDialog.setMessage("Loading product details. Please wait...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}
/**
* Getting product details in background thread
* */
protected String doInBackground(String... params) {
// updating UI from Background Thread
runOnUiThread(new Runnable() {
public void run() {
// Check for success tag
// TODO Auto-generated method stub
int success;
try {
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("pid", pid));
// getting product details by making HTTP request
// Note that product details url will use GET request
JSONObject json = jsonParser.makeHttpRequest(
url_order_detials, "GET", params);
// check your log for json response
Log.d("Single Product Details", json.toString());
// json success tag
success = json.getInt(TAG_SUCCESS);
if (success == 1) {
// successfully received product details
JSONArray productObj = json
.getJSONArray(TAG_GET); // JSON Array
// get first product object from JSON Array
JSONObject product = productObj.getJSONObject(0);
// product with this pid found
// Edit Text
mejaTv = (TextView) findViewById(R.id.meja);
customerTv = (TextView) findViewById(R.id.customer);
keteranganTv = (TextView) findViewById(R.id.keterangan);
// display product data in EditText
mejaTv.setText(product.getString(TAG_MEJA));
customerTv.setText(product.getString(TAG_CUST));
keteranganTv.setText(product.getString(TAG_KET));
}else{
// product with pid not found
}
} catch (JSONException e) {
e.printStackTrace();
}
}
});
return null;
}
/**
* After completing background task Dismiss the progress dialog
* **/
protected void onPostExecute(String file_url) {
// dismiss the dialog once got all details
pDialog.dismiss();
}
}
}
PHP 代码：
/*
* Following code will get single product details
* A product is identified by product id (pid)
*/
// array for JSON response
$response = array();
// include db connect class
require_once __DIR__ . '/db_connect.php';
// connecting to db
$db = new DB_CONNECT();
// check for post data
if (isset($_GET["pid"])) {
$pid = $_GET['pid'];
// get a product from products table
$result = mysql_query("SELECT *FROM penjualan WHERE pid = $pid");
if (!empty($result)) {
// check for empty result
if (mysql_num_rows($result) > 0) {
$result = mysql_fetch_array($result);
$product = array();
$product["pid"] = $result["pid"];
$product["meja"] = $result["meja"];
$product["customer"] = $result["customer"];
$product["keterangan"] = $result["keterangan"];
// success
$response["success"] = 1;
// user node
$response["get"] = array();
array_push($response["get"], $product);
// echoing JSON response
echo json_encode($response);
} else {
// no product found
$response["success"] = 0;
$response["message"] = "No product found";
// echo no users JSON
echo json_encode($response);
}
} else {
// no product found
$response["success"] = 0;
$response["message"] = "No product found";
// echo no users JSON
echo json_encode($response);
}
} else {
// required field is missing
$response["success"] = 0;
$response["message"] = "Required field(s) is missing";
// echoing JSON response
echo json_encode($response);
}
?>
我看过其他帖子的示例代码，但我不太明白如何应用它。可以给我示例代码吗？
【问题讨论】：
-
该查询是否正确？您在 * 之后错过了一个空格
-
首先检查您通过浏览器从 PHP 获得的响应。然后检查您的 JSON 是否被正确解析。在控制台上记录值。学习调试代码。
-
佩德罗眼光不错。还有你可以分享的日志吗？
-
我已经尝试寻找错误，但我不知道她的错误在哪里，这是我的第一个代码，如果从 SQLite 我能够向她展示，但从 MYSQL 对我来说非常困难，我有3天找到他的错，但我没有找到它
标签： java android mysql json textview