【发布时间】:2013-01-18 02:56:54
【问题描述】:
我正在尝试在 Eclipse 中创建我的第一个 MySQLConnection,但在 authenticateUser 上出现“此行有多个标记”的错误 - 返回类型不兼容 DBConnection.authenticateUser(String, String)"
我理解这意味着“存在不止一个错误……但我无法解决问题……”。
我使用http://altair.cs.oswego.edu/~tenberge/tenbergen.org/misc/DB-Access-in-GWT-The-Missing-Tutorial.pdf 作为我的向导。
这是我的代码:
AwardTracker.gwt.xml
<module>
<inherits name="com.google.gwt.user.User"/>
<inherits name="com.google.gwt.user.theme.standard.Standard"/>
<entry-point class="org.AwardTracker.client.AwardTracker"/>
<!-- servelet context - path is arbitrary, but must match up with the rpc init inside java class -->
<!-- Tomcat will listen for this from the server and waits for rpc request in this context -->
<servelet class="org.AwardTracker.server.MySQLConnection"
path="/MySQLConnection" />
<inherits name="com.google.gwt.user.theme.standard.Standard"/>
<inherits name="com.google.gwt.user.theme.chrome.Chrome"/>
<inherits name="com.google.gwt.user.theme.dark.Dark"/>
User.java
package org.AwardTracker.client;
import com.google.gwt.user.client.rpc.IsSerializable;
public class User implements IsSerializable {
@SuppressWarnings("unused")
private String username;
@SuppressWarnings("unused")
private String password;
@SuppressWarnings("unused")
private User() {
//just here because GWT wants it.
}
public User(String username, String password) {
this.username = username;
this.password = password;
}
}
MySQLConnection.java
package org.AwardTracker.server;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.util.Vector;
import com.google.gwt.user.server.rpc.RemoteServiceServlet;
import org.AwardTracker.client.DBConnection;
import org.AwardTracker.client.User;
public class MySQLConnection extends RemoteServiceServlet implements DBConnection {
private Connection conn = null;
private String status;
private String url = "jbdc:mysql://localhost/awardtracker";
private String user = "DBuser";
private String pass = "DBpass";
public MySQLConnection() {
try {
Class.forName("com.mysql.jdbc.Driver").newInstance();
conn = DriverManager.getConnection(url, user, pass);
} catch (Exception e) {
//NEVER catch exceptions like this
}
}
public int authenticateUser(String user, String pass) {
User user;
try {
PreparedStatement ps = conn.prepareStatement(
"select readonly * from users where username = \"" + user + "\" AND " + "password = \"" + pass + "\"");
ResultSet result = ps.executeQuery();
while (result.next()) {
user = new User(result.getString(1), result.getString(2));
}
result.close();
ps.close();
} catch (SQLException sqle) {
//do stuff on fail
}
return user;
}
}
任何帮助将不胜感激。
问候,
格林
嗨 BenvynQ,
感谢您的帮助。只是表明这些教程并不完美。我做了这个更改,现在在 authenticateUser 中出现错误:
while (result.next()) {
user = new User(result.getString(1), result.getString(2));
}
关于“构造函数 User(String, String) 未定义”。
谢谢,
格林
嗨,贝文克,
非常感谢您的帮助。我认为缺少一些“}”所以我修改如下。
另外,你说“User user = null; // 必要的,除非你在异常处理程序中做某事 “。我对此的印象是,我们试图找出用户是否在表中,如果不在则返回异常(即验证用户名和密码)。因此,返回需要是确认,因此我们正在使用 exveption 处理程序做一些事情。我显然遗漏了一些东西;那么我们如何知道用户已成功登录?
此外,Eclipse 似乎对包的混合大小写没有问题,因为我正在分阶段执行此操作,并且所有内容都已准备好添加此内容。
问候,
格林
package org.AwardTracker.server;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.util.Vector;
import com.google.gwt.user.server.rpc.RemoteServiceServlet;
import org.AwardTracker.client.DBConnection;
import org.AwardTracker.client.User;
public class MySQLConnection extends RemoteServiceServlet implements DBConnection {
private Connection conn = null;
private String status;
private String url = "jbdc:mysql://localhost/awardtracker";
private String user = "DBuser";
private String pass = "DBpass";
public MySQLConnection() {
try {
Class.forName("com.mysql.jdbc.Driver").newInstance();
conn = DriverManager.getConnection(url, user, pass);
} catch (Exception e) {
//NEVER catch exceptions like this
}
}
public User authenticateUser(String userName, String pass) {
User user = null; // necessary unless you do something in the exception handler
ResultSet result = null;
PreparedStatement ps = null;
try {
ps = conn.prepareStatement(
"select readonly * from users where username = \"" + userName + "\" AND " + "password = \"" + pass + "\"");
result = ps.executeQuery();
while (result.next()) {
user = new User(result.getString(1), result.getString(2));
}
}
catch (SQLException sqle) {
//do stuff on fail
}
finally {
if (result != null) {
try {
result.close();
}
catch (SQLException e) {
e.printStackTrace();
}
}
if (ps != null) {
try {
ps.close();
}
catch (SQLException e) {
e.printStackTrace();
}
}
}
return user;
}
}
【问题讨论】:
-
//NEVER catch exceptions like this... 除非你刚刚抓住它并丢弃它。我认为您的意思是没有 try/catch 块并让异常传播到方法之外。 -
gwt.xml 文件中的 GWT servlet 标记也是老派,如果您可以切换到最新的 GWT 2.5 和基于 annotation/web.xml 的方法。
-
嗨,SSR,你能指出我应该如何做的例子吗?这将不胜感激。 Regatds,格林