strtoul 从字符串日期（“03/10/2013 14:01:00”）转换为 time_t

Question

我不明白，为什么这不起作用？ PS：这段代码是从某个谷歌上找到的！

问题：我不知道为什么它应该起作用？这是否也考虑时区？！

  1 #include<stdio.h>
  2 #include <stdlib.h>
  3 #include <string>
  4 #include <time.h>
  5 int main()
  6 {
  7     std::string text("10/10/2013 14:01:00");
  8     const char* nptr = text.c_str();
  9     char* endptr = NULL;
 10     time_t seconds_from_epoch = strtoul(nptr, &endptr, 0);
 11     if (secs != 0)
 12         printf("Secs: %ld\n", secs);
 13     if (*nptr != '\0' && endptr && *endptr  == '\0') {
 14         printf("Secs: %ld\n", secs);
 15     } else {
 16         printf("Unable to convert\n");
 17     }
 18 }

Answer 1

这是错误的假设。

我就是这样做的：

 21     printf("************************\n");
 22     int day, month, yr, hr, min, sec, tzone;
 23     char* more = (char *)nptr;
 24     month = strtol(more, &more, 10);
 25     day = strtol(more+1, &more, 10);
 26     yr = strtol(more+1, &more, 10);
 27     hr = strtol(more+1, &more, 10);
 28     min = strtol(more+1, &more, 10);
 29     sec = strtol(more+1, &more, 10);
 30     tzone = strtol(more+1, &more, 10);
 31 
 32     printf("Month: %d, Day: %d, Year: %d, Hour: %d, Min: %d, Sec: %d, Tzone:     %d\n", 
 33             month, day, yr, hr, min, sec, tzone);

然后可以使用 struct tm 和 mktime。