FK (mysql-db) 使用 Sequelize.js答案

【问题标题】：FK (mysql-db) using Sequalize.jsFK (mysql-db) 使用 Sequelize.js
【发布时间】：2019-08-22 14:03:59
【问题描述】：

当我通过 Sequalize.js 将数据传递到我的数据库时，除了食物表中仍然为空的 FK“shops_ID”之外，所有内容都正确存储。

我读过其他类似的主题，但没有任何帮助。

我将不胜感激任何帮助/指导。

我正在使用带有以下 db-setup 的 mysql

Shops (mysql-table)
- id (pk)
- shopName

Food (mysql-table)
- id (pk)
- foodName
- shops_ID (fk connected to "id" in shops table)

shops.js

const Sequelize = require("sequelize");
const db = require("../database/db_shops.js"); //DB connection

const shops = db.sequelize.define(
  "shops",
  {
    id: {
      type: Sequelize.INTEGER,
      primaryKey: true,
      autoIncrement: true
    },
    shopName: {
      type: Sequelize.STRING
);
module.exports = shops;

food.js

"use strict";
const Sequelize = require("sequelize");
const db = require("../database/db_shops.js"); //DB connection
var shops = require("../models/shops");

const food = db.sequelize.define(
  "food",
  {
    id: {
      type: Sequelize.INTEGER,
      primaryKey: true,
      autoIncrement: true
    },
    foodName: {
      type: Sequelize.STRING
    },
    shops_ID: {
      type: Sequelize.INTEGER,
      references: {
        model: "shops",
        key: "id"
      }
    }
  }
);
module.exports = food;

association.js

const food = require("./food");
const shops = require("./shops");
food.belongsTo(shops, { foreignKey: "shops_ID" });
module.exports = { food: food, shops: shops };

（编辑）这就是我将数据发布到 mysql-db 的方式：

const express = require("express");
const router = express.Router();
const cors = require("cors");
const db = require("../models/association.js");
const Shops = db.shops;
const Foods = db.food;

router.use(cors());

router.post("/sell", (req, res, next) => {
  var data = req.body.foodDefined;
  var food = [];
  for (var i = 0; i < data.length; i++) {
    food.push({
      foodName: data[i].foodName,
    });
  }
  const shops = {
    shopsName: req.body.shopsName,
  };
  if (!errors.isEmpty()) {
    res.send(errors);
  } else {
    Shops.create(shops) 
      .then(Shops => {
        Foods.bulkCreate(food);
        res.json({ status: Shops.shopsName + " Registered!" });
      })
      .catch(err => {
        res.send("error: " + err);
      });
  }
});
module.exports = router;

【问题讨论】：

向我们展示您如何存储数据
@rkm 我已经添加了上面的代码

标签： javascript mysql database foreign-keys sequelize.js

【解决方案1】：

shops_ID 没有被存储，因为你没有设置它。 food 对象只有一个属性 foodName。您应该为每种食物添加商店 ID：

...
const preparedFood = food.map(item => {
  item.shops_ID = Shops.id;
  return item;
});
Food.bulkCreate(preparedFood);

值得注意的是，Foods.bulkCreate 是异步方法，这意味着当您发送响应时，food 尚未存储，如果失败，您将收到错误，因为您无法发送两个响应。要解决它，您可以使用 await 或在另一个 .then 块中发送响应。

【讨论】：