PHP MySQL CSV 文件导入页面

Question

我正在尝试创建一个 CSV 文件 PHP 上传页面，该页面采用最终用户文件并将其上传到 mysql 数据库中的新表中。用户通过文本框指定表名，该值使用会话存储，最终用户通过文件名输入选择 csv 文件。

我的connection.php 工作正常，并且我已将以下代码嵌入到页面中，但我在mysql 查询中不断收到语法错误。我可以一起执行这两个操作（即创建表和导入），还是需要单独执行？

欢迎任何想法..

<?php
session_start();

include "scripts/db_connection.php"; //Connect to Database

$_SESSION['tablename'] = $tablename;

$deleterecords = "TRUNCATE TABLE '$tablename'"; //empty the table of its current records
mysql_query($deleterecords);



//Upload File
if (isset($_POST['submit'])) {
if (is_uploaded_file($_FILES['filename']['tmp_name'])) {
    echo "<h1>" . "File ". $_FILES['filename']['name'] ." uploaded successfully." . "</h1>";
    echo "<h2>Displaying contents:</h2>";
    readfile($_FILES['filename']['tmp_name']);
}

//Import uploaded file to Database
$handle = fopen($_FILES['filename']['tmp_name'], "r");



while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
    $import="CREATE TABLE $tablename; INSERT into $tablename(item1,item2,item3,item4,item5) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]')";

    mysql_query($import) or die(mysql_error());
}

fclose($handle);

print "Import done";

//view upload form
}else {

print "Upload new csv by browsing to file and clicking on Upload<br />\n";

print "<form enctype='multipart/form-data' action='Upload_mobile.php' method='post'>";

print "Name of table to upload to:<br />\n";

print "<input size='50' type='text' name='tablename'><br />\n";

print "File name to import:<br />\n";

print "<input size='50' type='file' name='filename'><br />\n";

print "<input type='submit' name='submit' value='Upload'></form>";

}

?>

更新：好的，我使用了 mysqli 多查询，但我很困惑，因为页面/脚本运行时没有错误，但没有基于 $tablename 创建表或抛出错误。知道如何解决这个问题吗？

以下新更新的代码：

 <?php
 session_start();

 include "scripts/db_connection.php"; //Connect to Database

 $_SESSION['tablename'] = $tablename;

 $deleterecords = "TRUNCATE TABLE '$tablename'"; //empty the table of its current records
 mysqli_query($deleterecords);



 //Upload File
 if (isset($_POST['submit'])) {
 if (is_uploaded_file($_FILES['filename']['tmp_name'])) {
    echo "<h1>" . "File ". $_FILES['filename']['name'] ." uploaded successfully." . "</h1>";
    echo "<h2>Displaying contents:</h2>";
    readfile($_FILES['filename']['tmp_name']);
}

//Import uploaded file to Database
$handle = fopen($_FILES['filename']['tmp_name'], "r");



while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
    $import="CREATE TABLE $tablename; INSERT into     $tablename(item1,item2,item3,item4,item5) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]')";

    mysqli_multi_query($import) or die(mysqli_error());
   }

fclose($handle);

print "Import done";

//view upload form
 }else {

print "Upload new csv by browsing to file and clicking on Upload<br />\n";

print "<form enctype='multipart/form-data' action='Upload_mobile.php' method='post'>";

print "Name of table to upload to:<br />\n";

print "<input size='50' type='text' name='tablename'><br />\n";

print "File name to import:<br />\n";

print "<input size='50' type='file' name='filename'><br />\n";

print "<input type='submit' name='submit' value='Upload'></form>";

}


?>

UPDATE2：我尝试使用“LOAD DATA INFILE”从不同的角度来解决这个问题，但我仍然没有得到任何结果。首先，它没有创建表，但与数据库的连接正在工作。我不确定创建表的尝试是否失败，然后显然会停止其余部分。欢迎提出想法！？！

 <?php

 session_start();

 //connect to DB

 $_SESSION['Tablename'] = $Tablename;
 $_SESSION['filename'] = $filename;


 }

 if (isset($_POST['submit'])) {
 $createtable = mysqli_query($db, "CREATE TABLE $Tablename");
 mysqli_query($createtable) or die(mysqli_error());

 $importfile = "
    LOAD DATA INFILE '".$filename."'
           INTO TABLE results  CHARACTER SET utf8 FIELDS TERMINATED BY ','
           OPTIONALLY ENCLOSED BY '\"' IGNORE 1 LINES (name, description, price, shipping, quantity);
    ";

     mysqli_query($importfile) or die(mysqli_error());

    }

 {

print "Upload new csv by browsing to file and clicking on Upload<br />\n";

print "<form enctype='multipart/form-data' action='Upload_mobile.php' method='post'>";

print "Name of table to upload to:<br />\n";

print "<input size='50' type='text' name='Tablename'><br />\n";

print "File name to import:<br />\n";

print "<input size='50' type='file' name='filename'><br />\n";

print "<input type='submit' name='submit' value='Upload'></form>";

}


?>

Answer 1

这里有一个多查询。这意味着一个带有分号的字符串，然后是字符串中的其他语句。

要么将它们分开并单独调用它们，要么使用mysqli multi_query。

无论如何，您都应该离开 mysql* 库并使用 mysqli 或 PDO。