【发布时间】:2018-10-31 10:59:05
【问题描述】:
我需要在其中制作一个临时文件:
Partcode、MutationDate、MovementType、数量
每个零件代码的每个运动类型都有多个突变日期(最多可能有 9 个运动类型) 我需要获取每个部分代码的每个运动类型的最后一个突变日期以及随之而来的数量。
零件代码为 003307 的示例
003307 2018-05-31 1 -100
003307 2018-06-11 2 -33
003307 2018-04-25 3 +25
所有 9 种运动类型以此类推。
到目前为止我得到了什么:
create table #LMUT(
MutationDate T_Date
,PartCode T_Code_Part
,CumInvQty T_Quantum_Qty10_3
,MovementType T_Type_PMOverInvt
)
insert #LMUT(
MutationDate,
Partcode,
CumInvQty,
MovementType)
SELECT
cast (max(MOV.MutationDate) as date)
,MOV.PartCode
,INV.MutationQty
,INV.PMOverInvtType
FROM dbo.T_PartMovementMain as MOV
inner join dbo.T_PartMovementOverInvt as INV on
INV.PMMainCode=MOV.PMMainCode
WHERE
MOV.PartMovementType = 1
group by MOV.PartCode,INV.PMOverInvtType,INV.MutationQty,MOV.MutationDate
SELECT * FROM #LMUT where partcode='003007'
drop table #LMUT
结果:
2016-12-06 00:00:00.000 003007 -24.000 2
2016-09-29 00:00:00.000 003007 -24.000 2
2016-11-09 00:00:00.000 003007 -24.000 2
2016-11-22 00:00:00.000 003007 -24.000 2
2016-10-26 00:00:00.000 003007 -24.000 2
2016-09-12 00:00:00.000 003007 -42.000 2
2016-10-13 00:00:00.000 003007 -24.000 2
2016-12-03 00:00:00.000 003007 100.000 5
2017-01-12 00:00:00.000 003007 -48.000 2
2016-10-04 00:00:00.000 003007 306.000 7
不是我需要的,还有8次类型2
我还尝试了什么:
SELECT distinct MOV.Partcode,INV.PMOverInvtType,mov.MutationDate
FROM dbo.T_PartMovementMain as MOV
inner join dbo.T_PartMovementOverInvt as INV on
INV.PMMainCode=MOV.PMMainCode
WHERE
mov.MutationDate = (SELECT MAX (c.MutationDate) FROM
dbo.T_PartMovementMain as c
inner join dbo.T_PartMovementOverInvt as d on D.PMMainCode=c.PMMainCode
WHERE
C.PartMovementType = 1 AND
C.PartCode=mov.PartCode AND
D.PMMainCode = C.PMMainCode AND
D.PMOverInvtType=inv.PMOverInvtType
)
and MOV.PartMovementType = 1 and mov.partcode='003007'
order by MOV.Partcode,INV.PMOverInvtType
结果:
3007 2 2017-01-12 00:00:00.000
3007 5 2016-12-03 00:00:00.000
3007 7 2016-10-04 00:00:00.000
这就是我想要的,但我也需要获得数量。
【问题讨论】:
标签: sql sql-server distinct temp-tables