MySQL选择具有MAX的行检索每个组和其他字段中的最后一条记录

Question

这是一个表vehicle_connection_status，其中包含如下所示的数据：

+------------+-------------+---------------+-------------+--------------+
| "idStatus" | "vehicleId" | "isConnected" | "missionId" | "lastUpdate" |
+------------+-------------+---------------+-------------+--------------+
| "8"        | "1"         | "0"           | "1"         | "10"         |
| "9"        | "1"         | "1"           | "1"         | "9"          |
| "10"       | "2"         | "0"           | "1"         | "9"          |
| "11"       | "2"         | "1"           | "1"         | "8"          |
| "12"       | "3"         | "1"           | "1"         | "11"         |
| "13"       | "4"         | "0"           | "1"         | "9"          |
| "14"       | "4"         | "1"           | "1"         | "10"         |
| "15"       | "4"         | "0"           | "1"         | "11"         |
+------------+-------------+---------------+-------------+--------------+

如果我运行查询

select vehicleId, isConnected, max(lastUpdate) lasts    
from vehicle_connection_status 
where missionId =1 
group by vehicleId, isConnected

我会得到如下结果：

+-------------+---------------+---------+
| "vehicleId" | "isConnected" | "lasts" |
+-------------+---------------+---------+
| "1"         | "0"           | "10"    |
| "1"         | "1"           | "9"     |
| "2"         | "0"           | "9"     |
| "2"         | "1"           | "8"     |
| "3"         | "1"           | "11"    |
| "4"         | "0"           | "11"    |
| "4"         | "1"           | "10"    |
+-------------+---------------+---------+

我想要的是每个“vehicleId”具有最高“lasts”但具有“isConnected”和“vehicleId”字段的文件，我正在寻找的结果是：

+-------------+---------------+---------+
| "vehicleId" | "isConnected" | "lasts" |
+-------------+---------------+---------+
| "1"         | "0"           | "10"    |
| "2"         | "0"           | "9"     |
| "3"         | "1"           | "11"    |
| "4"         | "0"           | "11"    |
+-------------+---------------+---------+

基本上把“isconected”加到

select vehicleId, max(lastUpdate) lasts  
    from vehicle_connection_status where missionId =1 group by vehicleId

+-------------+---------+
| "vehicleId" | "lasts" |
+-------------+---------+
| "1"         | "10"    |
| "2"         | "9"     |
| "3"         | "11"    |
| "4"         | "11"    |
+-------------+---------+

我看过其他类似的问题：

Retrieving the last record in each group - MySQL

但我无法解决问题。

问题是我不知道如何在需要时避免按 isconnected 分组。

我收到以下错误：

/* Error de SQL (1055): Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'x.idStatus' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by */

我尝试过其他方法：

区别：

SELECT DISTINCT
  vehicleId,
  isconnected,
  lastUpdate
FROM vehicle_connection_status t1
WHERE lastUpdate in (SELECT
  MAX(t2.lastUpdate)
FROM vehicle_connection_status t2
GROUP BY vehicleId)

还有其他更深奥的，

select v1.vehicleId, v1.isConnected , v1.lastUpdate
    from vehicle_connection_status v1

inner join 
    (select v2.vehicleId, v2.isConnected , max(v2.lastUpdate) as latest
    from vehicle_connection_status v2 group by v2.vehicleId, v2.isConnected) vc

    on vc.vehicleId = v1.vehicleId and vc.latest = v1.lastUpdate


where v1.missionId =1 

但不起作用。

目前，我使用第一个查询以编程方式解析结果集来获取所需的结果，但这不是最佳解决方案。

测试：

DB-FIDDLE

Answer 1

你可以试试这个

SELECT 
    v1.vehicleId, v1.isConnected, v1.lastUpdate
FROM
    vehicle_connection_status v1
        JOIN
    (SELECT 
        vehicleId, MAX(lastUpdate) lastUpdate
    FROM
        vehicle_connection_status 
    GROUP BY vehicleId) v2 ON v1.vehicleId = v2.vehicleId
        AND v1.lastUpdate = v2.lastUpdate;