Python将乱码转换为希伯来语[关闭]

Question

这是我的代码：

# -*- coding: utf-8-*-
array=["à","á","â","ã","ä","å","æ","ç","è","é","ê","ë","ì","í","î","ï","ð","ñ","ó","ô","õ","ö","ø","ù","ú","û","ü","ý","þ","ÿ"]
array1=["א","ב","ג","ד","ה","ו","ז","ח","ט","י","ך","כ","ל","ם","מ","ן","נ","ס","ע","ף","פ","ץ","צ","ק","ר","ש","ת"]
str="áï éäåãä"
message=""
for i in range(0,len(str)):
   s=str[i]
   index=-1
   for j in range(0,len(array)):
       if(array[j]==s):
           index=j
           break
   if(index!=-1):
   message+=array1[index]
   print array1[index]
print message

错误是：

SyntaxError: EOL while scanning string literal

在第 2 行

我有一个希伯来语文本文件，但无论编码是什么，它总是以乱码显示。这是一个将其转换为希伯来语的 python 程序。原始文件在 IS0-8859-1

Answer 1

正如@Martijn 所建议的，正确解码您的原始文件将是一个更好的解决方案。如果您的文件是希伯来语但显示array 字符，则它可能显示为latin1 或cp1252 编码。 cp1255 看起来很接近。也许您的array1 不太正确。另请注意，字符串是可迭代的，因此您可以简化数组：

# coding: utf8
array  = u'àáâãäåæçèéêëìíîïðñóôõöøùúûüýþÿ'
array1 = u'אבגדהוזחטיךכלםמןנסעףפץצקרשת'
print(array)
print(array1)
print(array.encode('cp1252').decode('cp1255',errors='replace'))

上面的最后一行反转了“不正确”的编码，并改为使用cp1255（希伯来语编码）对其进行解码。输出：

àáâãäåæçèéêëìíîïðñóôõöøùúûüýþÿ
אבגדהוזחטיךכלםמןנסעףפץצקרשת
אבגדהוזחטיךכלםמןנסףפץצרשת��‎‏�

这不是一个完美的匹配，但足够接近，我认为您的原始文件是用 cp1255 编码的。

Answer 2

你使用了'，而你应该使用"：

'ÿ"

最后一个条目：

array=["à","á","â","ã","ä","å","æ","ç","è","é","ê","ë","ì","í","î","ï","ð","ñ","ó","ô","õ","ö","ø","ù","ú","û","ü","ý","þ",'ÿ"]

把那个单引号变成双引号。

至于你的翻译程序；听起来好像您的文件编码不正确，或者解码不正确。也许您应该找出正确的编码，而不是盲目地将拉丁语 1 字节替换为希伯来语代码点的 UTF-8 序列？

如果您使用codec 模块以正确的编解码器打开文件并解码为Unicode，您很可能会发现数据已正确编码。

我强烈建议您在继续之前学习 Unicode、编解码器和 Python：

• The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!) 乔尔·斯波尔斯基

• Python Unicode HOWTO

• Pragmatic Unicode by Ned Batchelder