bash 语法错误：不接受的令牌 Elif [关闭]

Question

我在运行一个简单的脚本后收到了这条消息：

第 9 行：意外标记 elif 附近的语法错误 第 9 行：elif [ $sales -le 20000 ];

我的代码：

    #!/bin/bash
    echo "Please enter the how much sales you have done"
    read sales
    if [ $sales -le 5000 ];
    then
       echo "your profit is $[$sales*0.25]"
    elif [ $sales -le 10000 ];
       echo "your profit is $[$sales*0.1]"
    elif [ $sales -le 20000 ];
       echo "your profit is $[$sales*0.15]"
    elif [ $sales -le 40000 ];
       echo "your profit is $[$sales*0.2]"
    else
       echo "your profit is $[$sales*0.25]"
    fi

Answer 1

1. 你在elif 之后缺少then
2. 您不能在 bash 中进行浮点数学运算。

你可以使用这个脚本：

#!/bin/bash
read -p "Please enter the how much sales you have done: " sales
if [ $sales -le 5000 ]; then
   pp='0.25'
elif [ $sales -le 10000 ]; then
   pp='0.1'
elif [ $sales -le 20000 ]; then
   pp='0.15'
elif [ $sales -le 40000 ]; then
   pp='0.2'
else
   pp='0.25'
fi
echo "your profit is " $(bc -l <<< "$sales * $pp")