【发布时间】:2017-03-06 01:00:09
【问题描述】:
我正在用 Rust 编写一些连接到远程服务器的代码,并根据该服务器发送的消息,计算一些统计数据或基于这些统计数据执行操作。但这对我来说更像是一个学习项目,我遇到了一个问题。
这是我为了重现问题而减少到最低限度的代码:
// Repro code for error[E0502]: cannot borrow `*self` as mutable because `self.server` is also borrowed as immutable
use std::collections::HashMap;
struct ServerReader {
server: Vec<u32>, // A vec for demo purposes, but please imagine this is a server object
counters: HashMap<u32, usize>,
}
impl ServerReader {
fn new() -> ServerReader {
ServerReader {
server: vec!(1, 2, 5, 2, 7, 9, 1, 1, 5, 6), // Filling my "server" with some messages
counters: HashMap::new(),
}
}
fn run(&mut self) {
println!("Connecting..."); // ... here there should be some code to connect to the server ...
for message in self.server.iter() { // We wait for the network messages sent by the server, and process them as they come
// ----------- immutable borrow occurs here
println!("Received {}", message);
self.process_message(*message); // HOW
// ^^^^ mutable borrow occurs here
}
// - immutable borrow ends here
println!("Disconnected");
}
fn process_message(&mut self, message: u32) {
// Please imagine that this function contains complex stuff
let counter = self.counters.entry(message).or_insert(0);
*counter += 1;
}
}
fn main() {
let mut reader = ServerReader::new();
reader.run();
println!("Done");
}
虽然我想我理解编译器为什么不满意,但我仍在努力想出一个解决方案。我无法在循环之外操纵我的结构,因为我必须在连接和收听服务器时工作。我也可以将所有内容直接放在循环中而不调用任何方法,但我不想以 1000 行循环结束(我更愿意了解实际解决方案的样子)。
【问题讨论】:
标签: rust borrow-checker