【发布时间】:2016-08-10 06:40:18
【问题描述】:
虽然我的文件名和位置设置正确,但插入时出现错误。有什么解决方案吗? 在此先感谢...这是我的代码:
// path where your CSV file is located
define('CSV_PATH','C:\xampp\htdocs\form');
// Name of your CSV file
$csv_file = CSV_PATH . "test.csv";
if (($handle = fopen($csv_file, "r")) !== FALSE) {
fgetcsv($handle);
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
for ($c=0; $c < $num; $c++) {
$col[$c] = $data[$c];
}
$col1 = $col[0];
$col2 = $col[1];
$col3 = $col[2];
$query = "INSERT INTO csvTable(ID,Name,city) VALUES ('".$col1."','".$col2."','".$col3."')";
$params = array();
$options = array( "Scrollable" => SQLSRV_CURSOR_KEYSET );
$stmt = sqlsrv_query($conn, $query, $params, $options );
}
fclose($handle);
}
echo "File data successfully imported to database!!";
//mysql_close($connect);
?>
错误消息:警告:fopen(C:\xampp\htdocs\formtest.csv): failed to 打开流:中没有这样的文件或目录 C:\xampp\htdocs\form\upload.php 第 15 行
【问题讨论】:
-
也许您错过了 CSV 文件名前的反斜杠?
$csv_file = CSV_PATH . "\test.csv"; -
没错。您可以按照以下清单快速找到此类问题的原因:stackoverflow.com/questions/36577020/…
标签: php sql-server-2012