【发布时间】：2013-11-19 18:59:14
【问题描述】：
我正在使用 cakephp 2.x 并尝试使用 Bake 生成代码。当我试着烤蛋糕的时候。以下是我在命令行中遇到的错误。
Microsoft Windows [Version 6.1.7601]
Copyright (c) 2009 Microsoft Corporation. All rights reserved.
C:\Users\victorm>cd c:\wamp\www\myappname\app\Console
c:\wamp\www\myappname\app\Console>cake bake all
Welcome to CakePHP v2.4.2 Console
App : Console
Path: c:\wamp\www\myappname\app\Console\
Bake All
Warning Error: include_once(c:\wamp\www\myappname\app\Console\Config\database.php): failed to open stream: No such file or directory in [C:\wamp\www\myappname\lib\Cake\Model\ConnectionManager.php, line 69]
Warning Error: include_once(): Failed opening 'c:\wamp\www\myappname\app\Console\Config\database.php' for inclusion (include_path='C:\wamp\www\myappname\lib;.;C:\php5\pear') in [C:\wamp\www\myappname\lib\Cake\Model\ConnectionManager.php, line 69]
Error: The datasource configuration "default" was not found in database.php
#0 C:\wamp\www\myappname\lib\Cake\Model\ConnectionManager.php(93): Connection
Manager::_getConnectionObject('default')
#1 C:\wamp\www\myappname\lib\Cake\Console\Command\Task\ModelTask.php(929): ConnectionManager::getDataSource('default')
#2 C:\wamp\www\myappname\lib\Cake\Console\Command\Task\ModelTask.php(866): ModelTask->getAllTables('default')
#3 C:\wamp\www\myappname\lib\Cake\Console\Command\Task\ModelTask.php(955): ModelTask->listAll('default')
#4 C:\wamp\www\myappname\lib\Cake\Console\Command\BakeShell.php(152): ModelTask->getName('default')
#5 C:\wamp\www\myappname\lib\Cake\Console\Shell.php(433): BakeShell->all()
#6 C:\wamp\www\myappname\lib\Cake\Console\ShellDispatcher.php(209): Shell->runCommand('all', Array)
#7 C:\wamp\www\myappname\lib\Cake\Console\ShellDispatcher.php(68): ShellDispatcher->dispatch()
#8 C:\wamp\www\myappname\app\Console\cake.php(37): ShellDispatcher::run(Array)
#9 {main}
c:\wamp\www\myappname\app\Console>
有人知道如何解决这个问题吗？
【问题讨论】：
标签： cakephp wamp command-line-interface