您如何比较三个列表并将重复项添加到一个列表而将非重复项添加到另一个列表？

Question

我需要设计一种方法来比较三个列表中的所有数字，并且如果所有三个列表中都存在一个数字 - 我必须将它添加到 matching_numbers 列表中。如果一个数字与其他任何数字都不匹配，那么我必须将它添加到 unique_numbers 列表中。我尝试使用 for 循环，但我只能完成等式的一半，而且我不确定如何将所有不匹配的数字添加到 unique_numbers 列表中。我也不希望我的 matching_numbers 或 unique_numbers 列表中有任何重复项。

list_1 = []

list_2 = []

list_3 = []

matching_numbers = []

unique_numbers = []

countone = 0

counttwo = 0

countthree = 0

import random

name = input("Hello USER. What will your name be?")

print("Hello " + name + ". Welcome to the NUMBERS program.")

amountone = int(input("How many numbers do you wish to have for your first list? Please choose from between 1 and 15."))

while countone != amountone:
  x = random.randint(1, 50)
  list_1 += [x,]
  print(list_1)
  countone += 1

amounttwo = int(input("For your second list, how many numbers do you wish to have? Please choose from between 1 and 15."))

while counttwo != amounttwo:
  x = random.randint(1, 50)
  list_2 += [x,]
  print(list_2)
  counttwo += 1

amountthree = int(input("For your third list, how many numbers do you wish to have? Please choose from between 1 and 15."))

while countthree != amountthree:
  x = random.randint(1, 50)
  list_3 += [x,]
  print(list_3)
  countthree += 1

for a in list_1:
    for b in list_2:
        for c in list_3:
          if a == b and b == c:
            matching_numbers = list(set(list_1) & set(list_2) & set(list_3))
          else:
            unique_numbers = 

Answer 1

这是Sets 最适合的类型。与列表不同，检查是否存在的复杂性为O(n)，集合查找为O(1)。此外，集合已经具有检查交叉点、差异等的方法。因此，三个集合中的项目可以计算为三个集合的交叉点：

all_numbers = set_1 | set_2 | set_3
matching_numbers = set_1 & set_2 & set_3
unique_numbers = all_numbers - matching_numbers