如果该属性值再次出现，则只需打印一次属性值就应该忽略它

Question

考虑一个表测试属性是（id，test_case，file_name，coverage） 因为我将从列表中获取多个文件名作为输入，所以我只需要显示一次 test_case 属性值。这是下面的例子：

import MySQLdb
out1=list()
out1=['cdp.c',ndp_arp_fusen.c','discovery.c']
db=MySQLdb.connect(host="localhost",user="root",passwd="vinay123",db="test")
cur=db.cursor()
for line in out1:
    cur.execute("select * from check2 where file_name like %s",("%"+line))
    rows=cur.fetchall()
    for row in rows:
        print(row)

我得到如下输出：

(3917L, 'test case1', 'cdp.c', 1L)
(7730L, 'test case2', 'cdp.c', 937L)
(9837L, 'test case3', 'cdp.c', 888L)
(11313L, 'test case4', 'cdp.c', 89L)
(15727L, 'test case5', 'cdp.c', 937L)
(19718L, 'test case6', 'cdp.c', 1L)
(25003L, 'test case7', 'cdp.c', 937L)
(25004L, 'test case7', 'cdp.c', 1L)
(25239L, 'test case8', 'cdp.c', 937L)
(25240L, 'test case8', 'cdp.c', 1L)
(3970L, 'test case1', 'ndp_arp_fusen.c', 81L)
(7780L, 'test case2', 'ndp_arp_fusen.c', 83L)
(15777L, 'test case5', 'ndp_arp_fusen.c', 83L)
(19771L, 'test case6', 'ndp_arp_fusen.c', 81L)
(25083L, 'test case7', 'ndp_arp_fusen.c', 83L)
(25084L, 'test case7', 'ndp_arp_fusen.c', 81L)
(3971L, 'test case1', 'discovery.c', 34L)
(7781L, 'test case2', '_discovery.c', 34L)
(9887L, 'test case3', 'discovery.c', 34L)
(10239L, 'test case4', 'discovery.c', 34L)
(15778L, 'test case5', 'discovery.c', 34L)
(19772L, 'test case6', 'discovery.c', 34L)
(25085L, 'test case7', 'discovery.c', 34L)
(25321L, 'test case8', 'discovery.c', 34L)

因为我需要 test_case 属性值来打印唯一的，也就是说我不需要重复的 test_case 名称。 我只需要一次test_case名称，输出应该如下：

(3917L, 'test case1', 'cdp.c', 1L)
(7730L, 'test case2', 'cdp.c', 937L)
(9837L, 'test case3', 'cdp.c', 888L)
(11313L, 'test case4', 'cdp.c', 89L)
(15727L, 'test case5', 'cdp.c', 937L)
(19718L, 'test case6', 'cdp.c', 1L)
(25003L, 'test case7', 'cdp.c', 937L)
(25239L, 'test case8', 'cdp.c', 937L)

Answer 1

您可以将看到的值保存在一组中以记住已经打印的值，然后跳过它们：

seen = set()
for line in out1:
    cur.execute("select * from check2 where file_name like %s",("%"+line))
    rows=cur.fetchall()
    for row in rows:
        if row[1] in seen:
            continue
        else:
            seen.add(row[1])
            print(row)