setw(n) 和对齐没有按我需要的方式工作 - C++

Question

这是我的上下文代码。这是我的第二个家庭作业介绍编程课程，我已经使用了我们在这个作业中学到的所有东西。我不允许使用任何我没有学过的东西。

我关心的部分是最底部的输出（注释为信息输出）。目前，我正在努力使所有内容完全正确对齐（右侧列中的最后一个字母或数字必须彼此对齐，就好像我是从右侧输入它们一样。

除了患者姓名、房间类型和在医院度过的天数之外的所有内容都正确对齐，小数对齐等等。将 setw(10) 更改为更大的值并没有任何好处（例如：我将它们全部设置为 setw(40)，但它仍然没有正确对齐任何东西。有什么想法吗？

#include <iostream>
#include <string>
#include <iomanip>
using namespace std;

//constants
const float PRIVATE = 125.00;
const float SEMI = 95.00;
const float WARD = 75.00;
const float TV = 3.50;
const float PHONE = 1.75;

int main()
{   //local variables
    string fname, lname, roomType, tvAccess, phoneAccess;
    int id, days;
    float roomBill, roomPrice, tvCharge, phoneCharge;
    bool error = false;

    //data collection/output
    cout << "Welcome to the hospital self-service program. Your bill will be calculated here.\n\n" << endl;
    cout << "Please enter your first and last name: ";
    cin >> fname;
    cin >> lname;
    cout << fname << " " << lname << ", please enter the four digit identification number found on your hospital wristband: ";
    cin >> id;
    cout << "Please enter the number of days spent in the hospital: ";
    cin >> days;
    cout << "\nEnter the type of room you stayed in: \nEnter P for room type: Private \nEnter S for room type: Semi-Private\nEnter W for room type: Ward \n" << endl;
    cin >> roomType;
    cout << "\nDid your room come with access to Television? Y/N: ";
    cin >> tvAccess;
    cout << "Did your room come with access to a Telephone? Y/N: ";
    cin >> phoneAccess;

    //if and elses
    if (roomType == "P" || roomType == "p")
    {
        error = false;
        roomType = "Private Room";
        roomPrice = PRIVATE;
    }
    else if (roomType == "S" || roomType == "s")
    {
        error = false;
        roomType = "Semi-Private Room";
        roomPrice = SEMI;

    }
    else if (roomType == "W" || roomType == "w")
    {
        error = false;
        roomType = "Ward Room";
        roomPrice = WARD;

    }
    else
    {
        cout << "Room type not valid. Exit the program and try again." << endl;
        error = true;
    }
    if (tvAccess == "Y" || tvAccess == "y")
        tvCharge = TV;
    else
        tvCharge = 0;

    if (phoneAccess == "Y" || phoneAccess == "y")
        phoneCharge = PHONE;
    else
        phoneCharge = 0;


    //information output
    cout << fixed << setprecision(2) << showpoint << endl;
    cout << setw(24) << left << "\n\nPatient Full Name: " << setw(10) << right << fname << " " << lname << endl;
    cout << setw(24) << left << "Identification Number: " << setw(10) << right << id << endl;
    cout << setw(24) << left << "Days spent in hospital: " << setw(10) << right << days << " day(s)" <<  endl;
    cout << setw(24) << left << "Room Type: " << setw(10) << right << roomType << endl;
    cout << setw(24) << left << "Room Charge: " << setw(10) << right << roomPrice * days << endl;
    cout << setw(24) << left << "Television Charge: " << setw(10) << right << tvCharge * days << endl;
    cout << setw(24) << left << "Telephone Charge: " << setw(10) << right << phoneCharge * days << endl;
    cout << setw(24) << left << "Total Charge: " << setw(10) << right << days * (phoneCharge + tvCharge + roomPrice) << endl;

    system("pause");
    return 0;
}

澄清一下。

Answer 1

它们的格式不正确的原因是，setw in

setw(10) << right << fname << " " << lname << endl;

和

setw(10) << right << days << " day(s)" <<  endl;

仅适用于第一个变量，即fname 和days。其他所有内容都只是附加。在此处使用setw 之前，您需要先连接这些字符串。