将不同的计数显示为每个返回值的单独列

Question

Table1（包含订单来源类型信息）

id | name
---------
 0 | App
 1 | Web

Table2（包含订单信息）

order_id | date_ordered | source_id 
   0     |   24/04/2016 |    0
   1     |   24/04/2016 |    1
   2     |   23/04/2016 |    0
   3     |   23/04/2016 |    1
   4     |   23/04/2016 |    0
   5     |   22/04/2016 |    1
   6     |   22/04/2016 |    0

我想显示给定日期每个来源的订单数

Date       | Source Count 0 | Source Count 1
24/04/2016 |       1        |       1
23/04/2016 |       2        |       1
22/04/2016 |       1        |       1

到目前为止我提出的查询：

SELECT
    date_ordered,
    count(distinct),
FROM `event`
 INNER JOIN `Table1`
    ON `id` = `Table2`.`source_id`
 GROUP BY date_ordered
ORDER BY date_ordered desc

我花了很多时间试图弄清楚，但想不出更好的办法。问题是来源的数量是动态的。

Answer 1

你可以用case和group by

 select date_ordered, 
 case when source_id = 0 then sum(source_id)
 END as  'Source Count 0',    
 case when source_id = 1 then sum(source_id)
 END as  'Source Count 1'
 group by date_ordered