【发布时间】:2018-06-12 10:15:02
【问题描述】:
我正在用 mysql 做一个 PHP CRUD,我遇到了一个我已经尝试了几个小时但无法解决的错误,有人可以帮助我吗?
正在显示的错误是:
致命错误:在 C 中对字符串调用成员函数 fetch_array (): \ wamp \ www \ crud_oop \ index.php 在第 233 行
第233行在while close_array中,有趣的是表中的第一项正常出现,而其余的却没有, 我还有其他代码块都采用相同的样式,但都正常工作,只有这一个出错了
<div class="container">
<div style="height:50px;"></div>
<div class="well" style="margin-left:auto; margin-right:auto; padding:auto; width:70%;">
<span style="font-size:25px; color:#1f1a2f"><strong>Sorteio</strong></span> <!-- BOTÕES -->
<span class="pull-right"><a href="#addnewPe" data-toggle="modal" class="btn btn-primary"><span class="glyphicon glyphicon-plus"></span> Adicionar</a></span>
<div style="height:15px;"></div>
<table class="table table-striped table-bordered table-hover">
<thead>
<th>Codigo</th>
<th>Data pedido</th>
<th>Cliente</th>
<th>Funcionário</th>
<th>Produto</th>
<th>Quantidade</th>
<th>Total do pedido</th>
<th>Ação</th>
</thead>
<tbody>
<?php
$query=$conn->query("SELECT * FROM tb_pedido Pp INNER JOIN tb_cliente C ON Pp.codCliente = C.codCliente INNER JOIN tb_funcionario F ON Pp.codFuncionario = F.codFuncionario INNER JOIN tb_produto P ON Pp.codProduto = P.codProduto");
while($row=$query->fetch_array()){
?>
<tr>
<td><?php echo $row['codPedido']; ?></td>
<td><?php echo $row['dataPedido']; ?></td>
<td><?php echo $row['nomeCliente']; ?></td>
<td><?php echo $row['nomeFuncionario']; ?></td>
<td><?php echo $row['descricao']; ?></td>
<td><?php echo $row['qtdVendida']; ?></td>
<td><?php echo $row['totalPedido']; ?></td>
<td>
<span class="pull-center"><a href="#delPp<?php echo $row['codPedido']; ?>" data-toggle="modal" class="btn btn-danger"><span class="glyphicon glyphicon-trash"></span></a></span>
<p>_____</p>
<span class="pull-center"><a href="#editPp<?php echo $row['codPedido']; ?>" data-toggle="modal" class="btn btn-warning"><span class="glyphicon glyphicon-edit"></span></a></span>
<?php include('pedido/button.php'); ?>
</td>
</tr>
<?php
}
?>
</tbody>
</table>
<?php
if(isset($_SESSION['msgPp'])){
?>
<div class="alert alert-success">
<?php echo $_SESSION['msgPp']; ?>
</div>
<?php
unset($_SESSION['msgPp']);
}
?>
</div>
<?php include('pedido/add_modal.php'); ?>
非常感谢您的帮助!
【问题讨论】:
-
你用的是mysql还是mysqli?
-
我正在使用 mysqli
-
这样试试 while($row=mysqli_fetch_array($query)){
-
pedido/button.php的内容是什么,希望它不会覆盖$query变量的值? -
警告:mysqli_fetch_array() 期望参数 1 为 mysqli_result,字符串中给出的这是我输入您请求的代码时给出的错误
标签: php mysql inner-join