在 2 个表格中列出成员的所有内容（问题、答案）

Question

想要列出个人的所有问题和所有答案。
我不知道我应该使用还是内部选择。

Tbquestions
id - 成员 - 问题 - 标题

Tbanswers
id - 成员 - 答案 - 标题

只需要获取每个表的标题

Answer 1

试试这个查询：

SELECT id,member,'Q' as Type, question as QA FROM Tbquestions
WHERE member='member1'
UNION ALL
SELECT id,member,'A' as Type, answer as QA FROM Tbanswers
WHERE member='member1'

样本输出：

id   member   Type   QA
1    Name1    Q      What is it?
3    Name4    Q      Who are you?
1    Name2    A      My name is Name2
4    Name3    A      He is dead, Jim.

编辑

为每个查询添加了Limit 子句，以找到 5 个问题和 10 个答案：

SELECT id,member,'Q' as Type, question as QA FROM Tbquestions
WHERE member='member1' LIMIT 5
UNION ALL
SELECT id,member,'A' as Type, answer as QA FROM Tbanswers
WHERE member='member1' LIMIT 10

Answer 2

如果问题和相应答案之间存在关系，则应进行连接。 由于这些表是通过成员 id 关联的，我认为不应该使用 join。而是使用 UNION ALL 从两个表中进行简单的选择和组合结果集

Answer 3

global $mysqli;

$stmt = $mysqli->prepare("SELECT title from Tbquestions WHERE member = ?");
$stmt->bind_param('s',$member);
if($stmt->execute()){
$stmt->bind_result($questions);
$stmt->close();
}
$stmt = $mysqli->prepare("SELECT title from Tbanswers WHERE member = ?");
$stmt->bind_param('s',$member);
if($stmt->execute()){
$stmt->bind_result($answers);
$stmt->close();
}
$allposts = array_merge($questions, $answers);
echo '<pre>';
print_r($allposts, false);