【发布时间】:2015-12-01 14:03:38
【问题描述】:
我有这 3 个这样的表:
讲师:
+-------------+---------+
| id-lecturer | name |
+-------------+---------+
| 1 | Johnson |
| 2 | Smith |
| ... | ... |
| ... | ... |
+-------------+---------+
主题:
+------------+---------+
| id-subject | name |
+------------+---------+
| 1 | Math |
| 2 | Physics |
| ... | ... |
| ... | ... |
+------------+---------+
考试:
+---------+-------------+------------+------------+
| id-exam | id-lecturer | id-subject | date |
+---------+-------------+------------+------------+
| 1 | 5 | 1 | 1990-05-05 |
| 2 | 7 | 1 | ... |
| 3 | 5 | 3 | ... |
| ... | ... | ... | ... |
+---------+-------------+------------+------------+
当我尝试做第一个选择时:
SELECT e.`id-lecturer`, e.`id-subject`, COUNT(e.`id-lecturer`) AS `exams-num`
FROM exams e
JOIN subjects s ON e.`id-subject`=s.`id-subject`
JOIN lecturers l ON e.`id-lecturer`=l.`id-lecturer`
GROUP BY e.`id-lecturer`, e.`id-subject`
我得到了正确的答案。它显示了类似的内容:
+-------------+------------+-----------+
| id-lecturer | id-subject | exams-num |
+-------------+------------+-----------+
| 0001 | 1 | 4 |
| 0001 | 3 | 1 |
| 0001 | 4 | 1 |
| 0001 | 5 | 1 |
| 0002 | 1 | 2 |
| 0002 | 2 | 1 |
| 0002 | 4 | 1 |
| 0002 | 6 | 3 |
+-------------+------------+-----------+
现在我只想显示每位讲师的最大人数,我的代码是:
SELECT it.`id-lecturer`, it.`id-subject`, MAX(it.`exams-num`) AS `exams-number`
FROM (
SELECT e.`id-lecturer`, e.`id-subject`, COUNT(e.`id-lecturer`) AS `exams-num`
FROM egzaminy e
JOIN subjects s ON e.`id-subject`=s.`id-subject`
JOIN lecturers l ON e.`id-lecturer`=l.`id-lecturer`
GROUP BY e.`id-lecturer`, e.`id-subject`) it
GROUP BY it.`id-lecturer`
输出:
+-------------+------------+--------------+
| id-lecturer | id-subject | exams-number |
+-------------+------------+--------------+
| 0001 | 1 | 4 |
| 0002 | 1 | 3 |
| 0003 | 1 | 2 |
| 0004 | 1 | 5 |
| 0005 | 2 | 1 |
+-------------+------------+--------------+
我得到每个讲师的最大值的正确数字,但主题 ID 不匹配,它总是采用第一行的 ID。我怎样才能使它正确匹配每一行中的这两个字段?
【问题讨论】:
-
不要使用'-'。这将导致一个痛苦的世界
-
感谢您的建议。幸运的是,这是我的大学讲师数据库。
-
一个恶毒的人,这是肯定的。
-
我试过了,结果还是一样。
标签: mysql select join count max