如何按月重新排序数据框的行？答案

【问题标题】：How to reorder the rows of a dataframe by month?如何按月重新排序数据框的行？
【发布时间】：2019-10-06 18:02:18
【问题描述】：

我的目标是按照月份（从 12 月、11 月、10 月等 到 1 月、2 月、3 月等）对数据框的行重新排序。) 每年。

目前我有以下数据框：

            Date            Title  Article
1   1 December 2000 PRESS CONFERENCE Article1
2   1 November 2000 PRESS CONFERENCE Article2
3    1 October 2000 PRESS CONFERENCE Article3
4  1 September 2000 PRESS CONFERENCE Article1
5     1 August 2000 PRESS CONFERENCE Article2
6       1 July 2000 PRESS CONFERENCE Article3
7       1 June 2000 PRESS CONFERENCE Article1
8             1 May PRESS CONFERENCE Article2
9      1 April 2000 PRESS CONFERENCE Article3
10     1 March 2000 PRESS CONFERENCE Article1
11  1 February 2000 PRESS CONFERENCE Article2
12   1 January 2000 PRESS CONFERENCE Article3
13   1 December 2001 PRESS CONFERENCE Article1
14   1 November 2001 PRESS CONFERENCE Article2
15   1 October 2001 PRESS CONFERENCE Article3
.
.
.
n    1 January 2001 PRESS CONFERENCE Article

这种结构从 2000 年到 2019 年一直存在。现在，我想把它颠倒过来，从 2000 年到 2019 年每年都得到这样的结果：

Date            Title  Article
1   1 January 2000 PRESS CONFERENCE Article1
2   1 February 2000 PRESS CONFERENCE Article2
3    1 March 2000 PRESS CONFERENCE Article3
4  1 April 2000 PRESS CONFERENCE Article1
5     1 May 2000 PRESS CONFERENCE Article2
6       1 June 2000 PRESS CONFERENCE Article3
7       1 July 2000 PRESS CONFERENCE Article1
8       1 August 2000 PRESS CONFERENCE Article2
9      1 September 2000 PRESS CONFERENCE Article3
10     1 October 2000 PRESS CONFERENCE Article1
11  1 November 2000 PRESS CONFERENCE Article2
12   1 December 2000 PRESS CONFERENCE Article3
13   1 January 2001 PRESS CONFERENCE Article1
14   1 February 2001 PRESS CONFERENCE Article2
15   1 March 2001 PRESS CONFERENCE Article3
.
.
.
n    1 December 2001 PRESS CONFERENCE Article

谁能帮我解决这个问题？我该怎么做？

非常感谢！

【问题讨论】：

标签： r dataframe

【解决方案1】：

将Date 转换为正确的格式，然后使用dplyr 中的arrange

library(dplyr)
df %>% arrange(lubridate::dmy(Date))

             Date Title
1  1 October 2000 PRESS
2 1 November 2000 PRESS
3 1 December 2000 PRESS
4  1 October 2001 PRESS
5 1 November 2001 PRESS
6 1 December 2001 PRESS

使用基础 R

df[order(as.Date(df$Date, "%d %B %Y")),]

数据

#Providing small dataset using `dput` will make it easier for other to help
df <- structure(list(Date = c("1 December 2000", "1 November 2000", 
"1 October 2000", "1 December 2001", "1 November 2001", "1 October 2001"
), Title = c("PRESS", "PRESS", "PRESS", "PRESS", "PRESS", "PRESS"
)), class = "data.frame", row.names = c("1", "2", "3", "13", 
"14", "15"))

【讨论】：

【解决方案2】：

我们可以从anytime使用anydate

library(dplyr)
library(anytime)
df %>%
    arrange(anydate(Date))

【讨论】：