【发布时间】:2015-10-12 19:08:51
【问题描述】:
我有 PHP 数组作为某个函数的日志,我正在为此准备日期明智的图表,
Array
(
[0] => 03-08-15 12:07:16 PM
[1] => 03-08-15 01:54:16 PM
[2] => 03-08-15 02:18:35 PM
[3] => 03-08-15 06:32:17 PM
[4] => 04-08-15 11:40:25 AM
[5] => 04-08-15 01:47:23 PM
[6] => 04-08-15 02:13:31 PM
[7] => 04-08-15 05:46:10 PM
[8] => 05-08-15 11:36:20 AM
[9] => 05-08-15 01:43:04 PM
[10] => 05-08-15 02:25:14 PM
[11] => 05-08-15 06:06:24 PM
[12] => 06-08-15 11:25:31 AM
[13] => 06-08-15 01:52:32 PM
... and so on
)
我想按日期重新排序,其中关键日期和值是内部数组,其中包含该特定日期的所有条目。
Array
(
[03-08-15] => Array
(
[0] => 12:07:16 PM
[1] => 01:54:16 PM
[2] => 02:18:35 PM
[3] => 06:32:17 PM
)
[04-08-15] => Array
(
[0] => 11:40:25 AM
[1] => 01:47:23 PM
[2] => 02:13:31 PM
[3] => 05:46:10 PM
)
[05-08-15] => Array
(
[0] => 11:40:25 AM
[1] => 01:47:23 PM
.....
)
and so on...
)
到目前为止,我已经尝试过
$tempArray = array();
foreach ($allEntries as $entry) {
$date = new DateTime($entry);
$tempArray[$date->format('m-d-y')] = $date->format('h:i:s A');
}
print_r($tempArray);
【问题讨论】:
-
你能分享你试过的代码吗? @Shadab
-
循环遍历数组,并将条目拆分为日期和时间。检查输出数组是否有日期条目,否则添加一个包含空数组的条目。然后将时间推到该子数组上。
-
@SubinThomas,现在检查。
-
足够接近,
$tempArray[$date->format('m-d-y')][] -
@Federico
$tempArray[$date->format('m-d-y')] = this part should be sub-array